Question

我正在使用ZF2中的服务，我需要将控制器和操作从已构建的路径中获取。那么有可能以某种方式从路线中获取动作和控制器吗？

扩展说明：

我尝试使用

$controller = $this->params()->fromRoute('controller');
$action = $this->params()->fromRoute('action');

但是我需要id fx我得到一个URL / accessadmin / addRole女巫是命名空间\ controller AccessAdmin \ Controller \ IndexController - ＆gt; addRoleAction（）

所以我需要一种方法将路由转换为AccessAdmin \ Controller \ IndexController并获取Action。

解决了结果

<?php
use Zend\Http\Request;

class IndexController extends AbstractActionController {

    public function indexAction()
    {
        // Uri example.
        $uri = '/accessadmin/resources/addRole/4';

        $request = new Request();
        $request->setUri($uri);

        /** @var $router \Zend\Mvc\Router\Http\TreeRouteStack */
        $router = $this->getServiceLocator()->get('Router');

        $routeMatch = $router->match( $request );
        if($routeMatch !== null ) {
            $controller = $this->getServiceLocator()->get('Config')['controllers']['invokables'][$routeMatch->getParam('controller')];
            $action = $routeMatch->getParam('action');
        }
        // Lazy test
        var_dump($controller);
        var_dump($action);

        return new ViewModel();
    }

}

?>

Answer 1

如果您要求从当前路线获取这些参数，那么它非常简单：

use Zend\Mvc\Controller\AbstractActionController;

class Index extends AbstractActionController {

    public function indexAction() {
        $controller = $this->params()->fromRoute('controller');
        $action = $this->params()->fromRoute('action');

        return new ViewModel();
    }
}

您可能还想知道给定URL字符串的控制器/操作参数是什么。在这种情况下，你可以像这样使用RouteMatch：

class Index extends AbstractActionController {

    public function indexAction() {

        $uri = '/accessadmin/addRole';

        $request = new Request();
        $request->setUri($uri);

        /** @var $router \Zend\Mvc\Router\Http\TreeRouteStack */
        $router = $this->getServiceLocator()->get('Router');

        $routeMatch = $router->match( $request );
        if($routeMatch !== null ) {
            $controller = $routeMatch->getParam('controller');
            $action = $routeMatch->getParam('action');
        }
    }
}

ZF2从路线获得控制器和动作

1 个答案: