Question

如何添加变量和数为42的数组并将其打印在数组的索引42中。谢谢你的帮助。我这样做但不能将变量添加到数字数组中，并且无法在数组中选择第42个变量

 static NSMutableArray * numberArray ;

- (void)applicationDidFinishLaunching:(NSNotification *)aNotification
{
    int currentIndex;
    int sumOfDigits;
    numberArray = [NSMutableArray array];

    for (int i=69999;i<80000;i++)
    {
        sumOfDigits= [self findTotalNumber:i];

        if(sumOfDigits==42)
        {
            currentIndex++;
            [numberArray addObject:[NSNumber numberWithInt:i]];
        }

        if(currentIndex>=42)
            break;
    }

    NSLog(@"the number of elements in the array %lu",[numberArray count]);
}

-(void)print42thVariable
{
    NSInteger index=41;
    NSLog (@"42th variable of array is  = %@", [numberArray objectAtIndex:index]);
}

-(int)findTotalNumber:(int)number
{
    int digit,sum=0, temp;
    temp = number;
    while(temp > 0) 
    {
        digit = temp%10;
        sum += digit;
        temp = temp/10;
    }
    NSLog(@"Sum of digits of %i = %i",number,sum);
    return number;
}

Answer 1

如果你想找到数字总和为42的第42个数字，那么你可以直接替换

NSLog(@"the number of elements in the array %lu",[numberArray count]);

带

NSLog(@"%i", [numberArray objectAtIndex:41])

这将打印出第42个元素。

Answer 2

似乎是微不足道的，你写了print42thVaribale，但你从来没有打电话给它。在Log ??

之后调用该方法

   NSLog(@"the number of elements in the array %lu",[numberArray count]);
   [self print42thVariable];

还需要更多修正，

-(int)findTotalNumber:(int)number
{
    int digit,sum=0, temp;
    temp = number;
    while(temp > 0) 
   {
      digit = temp%10;
      sum += digit;
      temp = temp/10;
    }
    NSLog(@"Sum of digits of %i = %i",number,sum);
    return sum; //Needs to be sum and not number
}

这应该不是问题，而是初始化变量的好习惯。

int sumOfDigits = 0;

如何将变量添加到数组并将其打印在数组的索引中

2 个答案: