Question

我如何将其转换为返回char *而不是使用std :: string 只想在没有std :: string

的情况下学习其他方法

string getName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address);

    int size = ReadCharSize();

    string name = "";

    for (int i = 0; i < size - 1; i++)
    {
        char c = ReadCharArrayChar(i);
        name += c;
    }

    return name;
}

Answer 1

其他方式很难看，这是std::string存在的原因之一:)。但出于教育目的，以下是您如何返回char*（如提出的那样）：

// caller is responsible for deleting the return value
char* getEntityName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address); // (not sure what this achieves)

    int size = ReadCharSize();

    char* name = new char[size];
    name[size - 1] = '\0';

    for (int i = 0; i < size - 1; i++)
    {
        char c = ReadCharArrayChar[i](); // odd looking, but I'll assume this works
        name[i] = c;
    }

    return name;
}

类似的选项仍然使用缓冲区的原始指针，但让调用者传入它（及其大小）：

// returns: true iff the buffer was successfully populated with the name
// exceptions might be a better choice, but let's keep things simple here
bool getEntityName(DWORD Address, char* buffer, int maxSize)
{
    DWORD BaseDword = ReadBaseDword(Address); // (not sure what this achieves?)

    int size = ReadCharSize();
    if(size > maxSize)
       return false;

    buffer[size - 1] = '\0';

    for (int i = 0; i < size - 1; i++)
    {
        char c = ReadCharArrayChar[i](); // odd looking, but I'll assume this works
        buffer[i] = c;
    }

    return true;
}

后一种选择允许，例如：

char buffer[100];
getEntityName(getAddress(), buffer, 100);

Answer 2

char * getEntityName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address);

    int size = ReadCharSize();

    char* name = malloc (size);

    for (int i = 0; i < size - 1; i++)
    {
        name[i] = ReadCharArrayChar[i]();
    }

    name[size - 1] = 0;

    return name;
}

请注意，调用者在完成后应该free返回值。这假定size包括终止零字节，它似乎给出了示例代码。

Answer 3

如果我绝对无法使用std::string，我会使用std::vector<char>：

std::vector<char> getName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address);

    const int size = ReadCharSize();

    std::vector<char> name(size);

    for (int i = 0; i < size - 1; i++)
    {
        name[i] = ReadCharArrayChar(i);
    }

    name[size - 1] = '\0';

    return name;
}

或std::unique_ptr<char[]>如果我知道调用者永远不需要修改结果：

std::unique_ptr<char[]> getName(DWORD Address)
{
    DWORD BaseDword = ReadBaseDword(Address);

    const int size = ReadCharSize();

    std::unique_ptr<char[]> name(new char[size]);

    for (int i = 0; i < size - 1; i++)
    {
        name[i] = ReadCharArrayChar(i);
    }

    name[size - 1] = '\0';

    return name;
}

读char到（char指针）

3 个答案: