Question

我很难弄清楚如何从具有子节点的SQL select创建XML文件来存储非唯一值。

我正在使用Microsoft SQL Server 2012

e.g。

select company, founder
from companies

查询结果为：

 microsoft corp       Bill Gates
 microsoft corp       Paul Allen
 apple inc            Steve Jobs
 apple inc            Ronald Wayne
 apple inc            Steve Wozniak

我想生成类似

的XML

<values>
       <company>microsoft corp</company>
       <founders>
           <founder id="1">Bill Gates</founder>
           <founder id="2">Paul Allen</founder>
       </founders>
</values>
<values>
       <company>apple inc</company>
       <founders>
           <founder id="1">Steve Jobs</founder>
           <founder id="2">Ronald Wayne</founder>
           <founder id="3">Steve Wozniak</founder>
        </founders>
       </company>
</values>

我不确定节点<founders>是否必需，我认为将创始人直接置于<values>节点之下也可以，因为他们保留在合适的公司，获得id有一个列表。

我现在使用FOR XML获得了什么，然后我尝试了以下不同的选项：

<values>
       <company>apple inc</company>
       <founder>Steve Jobs</founder>
</values>
<values>
       <company>apple inc</company>
       <founder>Ronald Wayne</founder>
</values>
<values>
       <company>apple inc</company>
       <founder>Steve Wozniak</founder>
</values>

与我当时需要达到的目标不相容。

非常感谢任何有助于让所有创始人置于同一<values>节点下的帮助。

谢谢！

Answer 1

搜索了一下互联网并找到了解决方案：

DECLARE @table TABLE (company VARCHAR(100), founder VARCHAR(100))

 insert into @table SELECT 'microsoft corp', 'Bill Gates'
 insert into @table SELECT 'microsoft corp', 'Paul Allen'
 insert into @table SELECT 'apple inc', 'Steve Jobs'
 insert into @table SELECT 'apple inc', 'Ronald Wayne'
 insert into @table SELECT 'apple inc', 'Steve Wozniak'


 SELECT company, 
    (
        SELECT ROW_NUMBER()OVER( ORDER BY founder ) as 'founder/@id',
            founder as 'founder'
        FROM @table as F
        WHERE F.company = Comp.company
        FOR XML PATH(''), TYPE
    ) AS founders
 FROM @table as Comp
 GROUP BY company
 FOR XML PATH('VALUES')

结果：

<VALUES>
  <company>apple inc</company>
  <founders>
    <founder id="1">Ronald Wayne</founder>
    <founder id="2">Steve Jobs</founder>
    <founder id="3">Steve Wozniak</founder>
  </founders>
</VALUES>
<VALUES>
  <company>microsoft corp</company>
  <founders>
    <founder id="1">Bill Gates</founder>
    <founder id="2">Paul Allen</founder>
  </founders>
</VALUES>

Answer 2

测试数据

DECLARE @Companies TABLE (company VARCHAR(100), founder VARCHAR(100))
INSERT INTO @Companies VALUES
 ('microsoft corp',       'Bill Gates'),
 ('microsoft corp',       'Paul Allen'),
 ('apple inc',            'Steve Jobs'),
 ('apple inc',            'Ronald Wayne'),
 ('apple inc',            'Steve Wozniak')

<强>查询

SELECT company
       ,(SELECT ROW_NUMBER() OVER (PARTITION BY Company ORDER BY Founder ASC)  AS [@ID] 
               ,B.founder [text()]
         FROM @companies B
        WHERE B.company = A.company
        FOR XML PATH('Founder'),TYPE) AS Founders
 FROM  @companies A
GROUP BY A.Company       
FOR XML PATH('values'),ROOT('Doc'), ELEMENTS

<强>输出

<Doc>
  <values>
    <company>apple inc</company>
    <Founders>
      <Founder ID="1">Ronald Wayne</Founder>
      <Founder ID="2">Steve Jobs</Founder>
      <Founder ID="3">Steve Wozniak</Founder>
    </Founders>
  </values>
  <values>
    <company>microsoft corp</company>
    <Founders>
      <Founder ID="1">Bill Gates</Founder>
      <Founder ID="2">Paul Allen</Founder>
    </Founders>
  </values>
</Doc>

SQL Server：使用子节点为非唯一值创建XML

2 个答案: