如何在MS SQL Server中连接两个列值

时间:2014-06-02 16:39:35

标签: php sql-server

我正在从PHP查询MS SQL Server数据库。该查询有效,但是当我尝试在first_name和last_name字段之间插入空格时,我收到错误。

当我这样写时,查询有效:

$query = 'SELECT meetings.name as Subject, 
                 meetings.date_entered, 
                 meetings.date_modified,
                 SELECT (users.first_name + users.last_name) as Fullname FROM dbo.users WHERE users.id = meetings.assigned_user_id';
if($custom_join) {
    $query .= $custom_join['select'];
}
$query .= ' FROM meetings ';

然而,当我写作时它失败了我试图在名字和姓氏之间加上一个空格,如下所示:

$query = 'SELECT meetings.name as Subject, 
                 meetings.date_entered, 
                 meetings.date_modified,
                 SELECT (users.first_name + ' ' + users.last_name) as Fullname    FROM dbo.users WHERE users.id = meetings.assigned_user_id';
if($custom_join) {
    $query .= $custom_join['select'];
}
$query .= ' FROM meetings ';

我得到的错误是''不是SQL表中的有效列或类似的列。

我用作(全名)的全名也是小写字母: - >全名。为什么这是大写' F'变成小写' f'?

我主要研究MySQL,但我对MS SQL相当新......有点奇怪。即使是Concat功能也不起作用。当我尝试使用它时,它告诉我它不是内置函数。

修改

$query = 'SELECT meetings.name as Subject, 
                 meetings.date_entered, 
                 meetings.date_modified,
                 (SELECT (users.first_name + ' ' + users.last_name) as Fullname    
                          FROM dbo.users WHERE users.id = meetings.assigned_user_id)';

编辑2:

$query = 'SELECT meetings.name as Subject, 
                 meetings.date_entered, 
                 meetings.date_modified,
                 SELECT (users.first_name + '' '' + users.last_name) as Fullname
                         FROM dbo.users WHERE users.id = meetings.assigned_user_id';
if($custom_join) {
    $query .= $custom_join['select'];
}
$query .= ' FROM meetings ';

4 个答案:

答案 0 :(得分:1)

你的字符串中的空格不变。

而不是'',请使用' '

请参阅此问题的SQLFiddle:SQL Fiddle

答案 1 :(得分:1)

如果使用CONCAT功能会怎样?

SELECT CONCAT(users.first_name, SPACE(1) ,users.last_name) AS Result  FROM dbo.users WHERE users.id = meetings.assigned_user_id

答案 2 :(得分:1)

从上下文来看,你似乎没有在SSMS中运行这个确切的查询,所以你可能错过了逃避你想要离开的单引号所需的额外单引号:

(SELECT users.first_name + '' '' +users.last_name as Fullname)

更新:我从你的问题更新中看到我是正确的,但你也有一个无效的查询,没有第二个FROM条款,很难确切地说出你所追求的是什么,但也许:

$query = 'SELECT meetings.name as Subject, 
                  meetings.date_entered, 
                  meetings.date_modified,
                  users.first_name + '' '' + users.last_name as Fullname    
          FROM dbo.users 
          JOIN dbo.meetings
             ON users.id = meetings.assigned_user_id)
              ';

答案 3 :(得分:0)

问题不在于连接,而是一个格式错误的SQL查询。串联问题是由单引号字符串中的单引号引起的。

以下代码应返回有效查询:

$query = "SELECT meetings.name as Subject, 
            meetings.date_entered, 
            meetings.date_modified,
            (SELECT users.first_name + ' ' + users.last_name 
            FROM dbo.users WHERE users.id = meetings.assigned_user_id
            ) as Fullname 
        ";
        //$query = 'SELECT meetings.*';

        if($custom_join) {
            $query .= $custom_join['select'];
        }
        $query .= " FROM meetings ";

这是查询的样子:

$query = "SELECT meetings.name as Subject, 
                meetings.date_entered, 
                meetings.date_modified,
                (SELECT users.first_name + ' ' + users.last_name) 
                FROM dbo.users WHERE users.id = meetings.assigned_user_id
                ) as Fullname
                FROM meetings";