Python：PyQt QTreeview示例 - 选择

Question

我正在使用Python 2.7和Qt设计器，我是MVC的新手： 我在Qt中完成了一个View，它给我一个目录树列表，并且控制器就位于运行状态。我的问题是：

鉴于Qtree视图，如果选择目录，我如何获取目录？

代码快照在下面，我怀疑它是SIGNAL（..）虽然我不确定：

class Main(QtGui.QMainWindow):
  plot = pyqtSignal()

  def __init__(self):
    QtGui.QMainWindow.__init__(self)
    self.ui = Ui_MainWindow()
    self.ui.setupUi(self)

    # create model
    model = QtGui.QFileSystemModel()
    model.setRootPath( QtCore.QDir.currentPath() )

    # set the model
    self.ui.treeView.setModel(model)

    **QtCore.QObject.connect(self.ui.treeView, QtCore.SIGNAL('clicked()'), self.test)**

  def test(self):
    print "hello!"

Answer 1

您正在寻找的信号由您的树拥有的 selectionModel 发出selectionChanged。此信号以选定的项作为第一个参数，取消选择作为第二个参数，两者都是QItemSelection的实例。

所以你可能想要改变这一行：

QtCore.QObject.connect(self.ui.treeView, QtCore.SIGNAL('clicked()'), self.test)

到

QtCore.QObject.connect(self.ui.treeView.selectionModel(), QtCore.SIGNAL('selectionChanged()'), self.test)

我还建议您使用new style for signals and slots。将您的test功能重新定义为：

 @QtCore.pyqtSlot("QItemSelection, QItemSelection")
 def test(self, selected, deselected):
     print("hello!")
     print(selected)
     print(deselected)

这里有一个有效的例子：

from PyQt4 import QtGui
from PyQt4 import QtCore

class Main(QtGui.QTreeView):

  def __init__(self):

    QtGui.QTreeView.__init__(self)
    model = QtGui.QFileSystemModel()
    model.setRootPath( QtCore.QDir.currentPath() )
    self.setModel(model)
    QtCore.QObject.connect(self.selectionModel(), QtCore.SIGNAL('selectionChanged(QItemSelection, QItemSelection)'), self.test)

  @QtCore.pyqtSlot("QItemSelection, QItemSelection")
  def test(self, selected, deselected):
      print("hello!")
      print(selected)
      print(deselected)

if __name__ == '__main__':
    import sys
    app = QtGui.QApplication(sys.argv)
    w = Main()
    w.show()
    sys.exit(app.exec_())

PyQt5

在PyQt5中有点不同（感谢Carel和saldenisov的评论和aswer。）

  

...当PyQt从4变为5时，连接从对象方法移动到作用于该属性的方法

相反，已知：

QtCore.QObject.connect(self.ui.treeView, QtCore.SIGNAL('clicked()'), self.test)

现在你写道：

class Main(QTreeView):
    def __init__(self):
        # ...  
        self.setModel(model)
        self.doubleClicked.connect(self.test)  # Note that the the signal is now a attribute of the widget.

以下是使用PyQt5的示例（由saldenisov提供）。

from PyQt5.QtWidgets import QTreeView,QFileSystemModel,QApplication

class Main(QTreeView):
    def __init__(self):
        QTreeView.__init__(self)
        model = QFileSystemModel()
        model.setRootPath('C:\\')
        self.setModel(model)
        self.doubleClicked.connect(self.test)

    def test(self, signal):
        file_path=self.model().filePath(signal)
        print(file_path)


if __name__ == '__main__':
    import sys
    app = QApplication(sys.argv)
    w = Main()
    w.show()
    sys.exit(app.exec_())

Answer 2

在PyQt5中，可以这样做：

from PyQt5.QtWidgets import QTreeView,QFileSystemModel,QApplication

class Main(QTreeView):
    def __init__(self):
        QTreeView.__init__(self)
        model = QFileSystemModel()
        model.setRootPath('C:\\')
        self.setModel(model)
        self.doubleClicked.connect(self.test)

    def test(self, signal):
        file_path=self.model().filePath(signal)
        print(file_path)


if __name__ == '__main__':
    import sys
    app = QApplication(sys.argv)
    w = Main()
    w.show()
    sys.exit(app.exec_())

Answer 3

如果我正确理解了这个问题，您希望选择目录或文件名。

这就是我的所作所为：

from PyQt4 import QtGui
from PyQt4 import QtCore

# ---------------------------------------------------------------------
class MainWindow(QtGui.QMainWindow):
    def __init__(self, parent=None):
        super().__init__(parent)

        self.resize(600,400)
        self.setWindowTitle("Treeview Example")

        self.treeview = QtGui.QTreeView(self)

        self.treeview.model = QtGui.QFileSystemModel()
        self.treeview.model.setRootPath( QtCore.QDir.currentPath() )
        self.treeview.setModel(self.treeview.model)
        self.treeview.setColumnWidth(0, 200)

        self.setCentralWidget(self.treeview)

        self.treeview.clicked.connect(self.on_treeview_clicked)

# ---------------------------------------------------------------------

    @QtCore.pyqtSlot(QtCore.QModelIndex)
    def on_treeview_clicked(self, index):
        indexItem = self.treeview.model.index(index.row(), 0, index.parent())

        # path or filename selected
        fileName = self.treeview.model.fileName(indexItem)
        # full path/filename selected
        filePath = self.treeview.model.filePath(indexItem)

        print(fileName)
        print(filePath)

# ---------------------------------------------------------------------

if __name__ == '__main__':
    import sys
    app = QtGui.QApplication(sys.argv)
    w = MainWindow()
    w.show()
    sys.exit(app.exec_())

Answer 4

我尝试了这个替代方法来获取文件名......

而不是：

indexItem = self.treeview.model.index(index.row(), 0, index.parent())

# path or filename selected
fileName = self.treeview.model.fileName(indexItem)

我试过了：

# path or filename selected
fileName = index.internalPointer().fileName

这似乎也有效......