Question

我的问题是如何从以下日期获得：mm / dd / yyyy 到2014年4月26日星期六？

在div中，我的日期为rel，

<td class="td-time" rel="06/02/14">09.00</td>

的js

var firstRowDate = $('.td-time:first-child').attr('rel');
var date = new Date(firstRowDate);

我确实尝试过这样：

var n = firstRowDate.getDay();

但我收到错误：undefined is not a function

Answer 1

如果您的日期对象是有效日期，那么

var firstRowDate = $('.td-time:first-child').attr('rel');
var date = new Date(firstRowDate);
var dateString = date.toDateString();

你应该看一下http://www.w3schools.com/jsref/jsref_obj_date.asp。您需要的所有日期js功能列表。

jsfiddle尝试：http://jsfiddle.net/Grimbode/sn6hQ/

Answer 2

如果您有月/日/年格式的字符串，则可以使用以下函数将其转换为日期名称日期月份名称年份格式：

// s is date in m/d/y format
function convertMDYstring(s) {

  var b = s.split(/\D/);
  var d = new Date(b[2],--b[0],b[1]);

  // Replace with day names in appropriate language
  var days = ['Sunday','Monday','Tuesday','Wednesday',
              'Thursday','Friday','Saturday'];

  // Replace with month names in appropriate language
  var months = ['January','February','March','April','May','June','July',
                'August', 'September','October','November','December'];

  // Helper for padding single digit values
  function z(n){return (n<10? '0' : '') + n;}

  return days[d.getDay()] + ' ' + d.getDate() + ' ' +
         months[d.getMonth()] +  ' ' + d.getFullYear();
}

Answer 3

 var d = new Date("1/05/2014");
 var months = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'Jun', 'Jul', 'Aug', 'Sep', 'Oct', 'Nov', 'Dec'];<br>
 var days = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'];<br>
 var date =days[d.getDay()]+" "+ d.getDate() + " " + months[d.getMonth()] + " " + d.getFullYear();

 alert(date);

Answer 4

在你的代码中，你做错了什么：

我确实尝试过这样：

var n = firstRowDate.getDay（）;

此处firstRowDate不是日期时间变量/对象。

你应该尝试那样 -

var n = date.getDay()

Demo

根据你的问题标题：

var dd = new Date($('.td-time').attr('rel'));
var weekday = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
var months = new Array('January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December');
var curMonth = months[dd.getMonth()];
var dayOfWeek = weekday[dd.getDay()];
alert(dayOfWeek + " " + dd.getDate() + " " + curMonth + " " + dd.getFullYear());

Working Example

Answer 5

您可以使用我在下面添加的代码段将日期转换为几乎任何格式。

对于您的案例，您需要执行此操作：

<强>代码：

dateFormat(new Date(),"dddd d mmmm yyyy")

<强>输出

Monday 2 June 2014"

其他示例

// Can also be used as a standalone function
dateFormat(new Date(), "dddd, mmmm dS, yyyy, h:MM:ss TT");
// Saturday, June 9th, 2007, 5:46:21 PM

<强>段：

将以下代码link添加到您的代码中。

var dateFormat = function () {
    var token = /d{1,4}|m{1,4}|yy(?:yy)?|([HhMsTt])\1?|[LloSZ]|"[^"]*"|'[^']*'/g,
        timezone = /\b(?:[PMCEA][SDP]T|(?:Pacific|Mountain|Central|Eastern|Atlantic) (?:Standard|Daylight|Prevailing) Time|(?:GMT|UTC)(?:[-+]\d{4})?)\b/g,
        timezoneClip = /[^-+\dA-Z]/g,
        pad = function (val, len) {
            val = String(val);
            len = len || 2;
            while (val.length < len) val = "0" + val;
            return val;
        };

    // Regexes and supporting functions are cached through closure
    return function (date, mask, utc) {
        var dF = dateFormat;

        // You can't provide utc if you skip other args (use the "UTC:" mask prefix)
        if (arguments.length == 1 && Object.prototype.toString.call(date) == "[object String]" && !/\d/.test(date)) {
            mask = date;
            date = undefined;
        }

        // Passing date through Date applies Date.parse, if necessary
        date = date ? new Date(date) : new Date;
        if (isNaN(date)) throw SyntaxError("invalid date");

        mask = String(dF.masks[mask] || mask || dF.masks["default"]);

        // Allow setting the utc argument via the mask
        if (mask.slice(0, 4) == "UTC:") {
            mask = mask.slice(4);
            utc = true;
        }

        var _ = utc ? "getUTC" : "get",
            d = date[_ + "Date"](),
            D = date[_ + "Day"](),
            m = date[_ + "Month"](),
            y = date[_ + "FullYear"](),
            H = date[_ + "Hours"](),
            M = date[_ + "Minutes"](),
            s = date[_ + "Seconds"](),
            L = date[_ + "Milliseconds"](),
            o = utc ? 0 : date.getTimezoneOffset(),
            flags = {
                d:    d,
                dd:   pad(d),
                ddd:  dF.i18n.dayNames[D],
                dddd: dF.i18n.dayNames[D + 7],
                m:    m + 1,
                mm:   pad(m + 1),
                mmm:  dF.i18n.monthNames[m],
                mmmm: dF.i18n.monthNames[m + 12],
                yy:   String(y).slice(2),
                yyyy: y,
                h:    H % 12 || 12,
                hh:   pad(H % 12 || 12),
                H:    H,
                HH:   pad(H),
                M:    M,
                MM:   pad(M),
                s:    s,
                ss:   pad(s),
                l:    pad(L, 3),
                L:    pad(L > 99 ? Math.round(L / 10) : L),
                t:    H < 12 ? "a"  : "p",
                tt:   H < 12 ? "am" : "pm",
                T:    H < 12 ? "A"  : "P",
                TT:   H < 12 ? "AM" : "PM",
                Z:    utc ? "UTC" : (String(date).match(timezone) || [""]).pop().replace(timezoneClip, ""),
                o:    (o > 0 ? "-" : "+") + pad(Math.floor(Math.abs(o) / 60) * 100 + Math.abs(o) % 60, 4),
                S:    ["th", "st", "nd", "rd"][d % 10 > 3 ? 0 : (d % 100 - d % 10 != 10) * d % 10]
            };

        return mask.replace(token, function ($0) {
            return $0 in flags ? flags[$0] : $0.slice(1, $0.length - 1);
        });
    };
}();

// Some common format strings
dateFormat.masks = {
    "default":      "ddd mmm dd yyyy HH:MM:ss",
    shortDate:      "m/d/yy",
    mediumDate:     "mmm d, yyyy",
    longDate:       "mmmm d, yyyy",
    fullDate:       "dddd, mmmm d, yyyy",
    shortTime:      "h:MM TT",
    mediumTime:     "h:MM:ss TT",
    longTime:       "h:MM:ss TT Z",
    isoDate:        "yyyy-mm-dd",
    isoTime:        "HH:MM:ss",
    isoDateTime:    "yyyy-mm-dd'T'HH:MM:ss",
    isoUtcDateTime: "UTC:yyyy-mm-dd'T'HH:MM:ss'Z'"
};

// Internationalization strings
dateFormat.i18n = {
    dayNames: [
        "Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat",
        "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"
    ],
    monthNames: [
        "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec",
        "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"
    ]
};

// For convenience...
Date.prototype.format = function (mask, utc) {
    return dateFormat(this, mask, utc);
};

mm / dd / yyyy到2014年4月26日星期六

5 个答案: