弹出showAtLocation不起作用

时间:2014-06-02 10:12:56

标签: android android-popupwindow

我在点击编辑文本时使用弹出窗口显示一些文本视图。但pop窗口没有显示在特定位置,它总是显示在左上角,这里是我的代码,有什么问题

    private void showPopup(Context context,final LinearLayout Parent) {


    LayoutInflater layoutInflater = (LayoutInflater)context
      .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    layout = layoutInflater.inflate(R.layout.popup,MainActivity.parent,true);
    // Creating the PopupWindow
    final PopupWindow popupWindow = new PopupWindow(
               layout,700,700);


    popupWindow.setContentView(layout);
    popupWindow.setHeight(500);


    new Runnable(){
        @Override
        public void run() {

            popupWindow.showAtLocation(layout, Gravity.CENTER,300,150);
        }

    };


    }

1 个答案:

答案 0 :(得分:2)

尝试以下代码:

public static Rect locateView(View v)
{
    int[] loc_int = new int[2];
    if (v == null) return null;
    try
    {
        v.getLocationOnScreen(loc_int);
    } catch (NullPointerException e)
    {
        //Happens when the view doesn't exist on screen anymore.
        return null;
    }
    Rect location = new Rect();
    location.left = loc_int[0];
    location.top = loc_int[1];
    location.right = location.left + v.getWidth();
    location.bottom = location.top + v.getHeight();
    return location;
}

然后使用

popup.showAtLocation(parent, Gravity.TOP|Gravity.LEFT, location.left, location.bottom);

希望它有所帮助...