使用单个表创建多维数组

Question

我有一张这样的桌子;

**Year**   **Month**
2012        Jan
2012        Mar
2012        Apr
2013        Dec
2013        Nov

我正在尝试从此表创建一个类似于下面的数组;

Array
(
    [2012] => Array(
              Jan, Mar, Apr),
    [2013] => Array(
              Dec, Nov)
);

到目前为止，我尝试了这段代码，但没有得到我想要的内容，

    while ($row = mysql_fetch_array($result)){

          $new_array[] = array(
            'year' => $row['year'],
            'month' => $row['month'],
          );
}

Answer 1

试试这个

while ($row = mysql_fetch_array($result)){
          $new_array[$row['year']][] = $row['month'];
}

Answer 2

更好的解决方案是使用MySQL的GROUP_CONCAT和GROUP来创建每年一行的结果，然后使用PHP的explode来分割GROUP_CONCAT为数组赋值：

$query = mysql_query("SELECT `year`, GROUP_CONCAT(`month`) AS `months` FROM table GROUP BY `year`");
$new_array = array();
while ($row = mysql_fetch_array($result)) {
    $new_array[$row['year']] = explode(',', $row['months']);
}

Answer 3

$new_array=array();
while ($row = mysql_fetch_array($result)){

      if(!isset($new_array[$row['year']])
        $new_array[$row['year']]=array();

       $new_array[$row['year']] = array_push($new_array[$row['year']],$row['month']);
}

Answer 4

将while循环更改为：

while ($row = mysql_fetch_array($result)){
      $new_array[$row['year']][] = $row['month'];
}

Answer 5

请尝试以下行 在循环外部创建数组。

 $newArray=array();
    while($row=mysql_fetch_array($(result))
    $newArray[$row['year']] = $row['month'];