Question

我有以下数据库结构，我想从特定用户和月份中选择所有内容。但它会返回特定的用户数据，但是所有月份都会返回我在此示例中选择的月份是2014-02或2014年2月

date       |user      | some more data |
----------------------------------------
2014-01-20 |user1     | more data      | //will not be skipped
2014-02-01 |user1     | more data      |
2014-02-01 |user2     | more data      | //will be skipped
2014-02-02 |user1     | more data      |
2014-05-02 |user1     | more data      | //will not be skipped

我通过预准备语句函数调用以下查询。 LIKE运算符似乎不起作用。

$query = "SELECT * FROM table1 WHERE user = ? AND date LIKE ?"
$user = "user1";     //These 2 actually come from user input so:
$date = "2014-02%";  //$user = $username; $date = $y."-".$m."%";
//function that runs the prepared statement (simplified)
//this function works for all other queries.
$result = $database->runQuery($query, array($user, $date));
while($row = mysqli_fetch_array($result){
    echo $row['date'];
    echo $row['user'];
    echo $row['some more data'];
    echo "<br>";
}

打印

2014-01-20 user1 more data //this line should not be printed but it does.
2014-02-01 user1 more data
2014-02-02 user1 more data
2014-05-02 user1 more data //also should not be printed.

所以我的问题是我在LIKE运算符中做错了什么？

我的实际查询。

//The system holds phone call data.
//dcontext is a variable that decides in which column the user is found.
//in case of dcontext = outgoing calls
//clid = username + extensions
//src = users phone number
//dst = to phone number (this can be extension from another user in the system)
//which wont be registered double in this case.

//when dcontext = incomming calls
//clid and src = the caller ID/phone number from the person calling.
//dst  = the users phone number.

//when dcontext = internal call transfer
//clid = username + extension
//src = users phone number
//dst = transfered number

"SELECT * FROM table WHERE 
(dcontext = ? AND (clid = ? OR src = ? OR dst = ? OR dst = ?)) OR 
(dcontext = ? AND dst = ?) OR 
(dcontext = ? AND (clid = ? OR src = ?)) AND 
date LIKE ?" 

date type = DateTime

Answer 1

请勿使用like。使用WHERE user = ? and year(date) = ? and month(date) = ?，假设数据是Date或DateTime类型，而不是varchar。

Answer 2

我认为你应该CAST将你的约会日期改为string格式，所以请尝试：

SELECT * FROM table1 WHERE user = ? AND CAST(date as char) LIKE ?

或使用DATE_FORMAT功能

SELECT * FROM table1 WHERE user = ? AND DATE_FORMAT(date, '%Y-%m-%d') LIKE ?

修改：

过滤日期部分的另一种方法是extract他们的部分：

SELECT * FROM table1 WHERE user = ? AND EXTRACT(year FROM date) = ? AND EXTRACT(month from date) = ?

但是你必须将year和month作为单独的参数传递

<强> EDIT2 ：

我将查询的一些元素放在大括号中，以确保您的AND运算符正常工作

尝试使用此查询：

SELECT * FROM table WHERE ((dcontext = ? AND (clid = ? OR src = ? OR dst = ? OR dst = ?)) OR (dcontext = ? AND dst = ?) OR (? AND (clid = ? OR src = ?))) AND (EXTRACT(year FROM date) = ? AND (EXTRACT(month FROM date) = ? )

如何使用LIKE运算符搜索一个月中的日期？

2 个答案: