有谁知道如何解决这个问题?我现在正在研究集体智慧,我在制作这段代码时与另一个例子进行了比较。但是这样会出现错误:
Traceback (most recent call last): File "<pyshell#8>", line 1, in
<module>
clust=clusters.hcluster(data) File "D:\Kuliah\smt1\Phyton Class\contoh coding\coding-collective
intelligence\myself_Maulida\bab3-documentClustering\clusters.py", line
78, in hcluster
for i in range(len(clust[0].vec))] TypeError: 'float' object has no attribute '__getitem__'
这是我的代码,任何人都可以提供帮助吗?谢谢。
def hcluster(rows,distance=pearson):
distances={}
currentclustid=-1
#clusters are initially just the rows
clust=[bicluster(rows[i],id=i) for i in range(len(rows))]
while len(clust)>1:
lowestpair=(0.1)
closest=distance(clust[0].vec,clust[1].vec)
#loop through every pair looking for the smallest distance
for i in range(len(clust)):
for j in range(i+1,len(clust)):
#distance is the cache of distance calculations
if(clust[i].id,clust[j].id) not in distances:
distances[(clust[i].id,clust[j].id)]=distance(clust[i].vec,clust[j].vec)
d=distances[(clust[i].id,clust[j].id)]
if d<closest:
closest=d
lowestpair=(i,j)
#calculate the average of the two cluster
mergevec=[
(clust[lowestpair[0]].vec[i]+clust[lowestpair[1]].vec[i])/2.0
for i in range(len(clust[0].vec))]
#create the new cluster
newcluster=bicluster(mergevec,left=clust[lowestpair[0]],
right=clust[lowestpair[1]],
distance=closest,id=currentclustid)
#cluster ids that weren't in the original set are negative
currentclustid-=1
del clust[lowestpair[1]]
del clust[lowestpair[0]]
clust.append(newcluster)
return clust[0]
答案 0 :(得分:1)
lowestpair=(0.1)
这是一个时期,而不是逗号。 lowestpair
是一个浮点数,而不是一个元组。 (虽然看起来错误来自clust[0]
,但Python回溯并不能很好地指出错误来自逻辑行的哪条物理线。)