Bluebird承诺 - 如何爆炸数组,然后映射它?

时间:2014-06-02 01:56:45

标签: javascript promise bluebird

如果我有一个数组:

['one.html','two.html','three.html']

我怎么能爆炸那个数组,对它应用一连串的承诺,然后再将它重新组合在一起?目前我的代码是这样的:

Promise.map(['one','two','three'], function(i) {
    dbQuery('SELECT ' + i);
}).then(function(results) {
    // This has an array of DB query results
});

我想象的是:

Promise.map(['one','two','three'], function(i) {
    dbQuery('SELECT ' + i);
})
.explode()
.then(function(result) {
    // Individual result
})
.combine()
.then(function(results) {
    // Now they're back as an array
});

现在,我知道蓝鸟没有这些功能,所以我想知道正确的Promise-y方式是做什么的?

2 个答案:

答案 0 :(得分:15)

您可以使用一系列地图:

Promise.map(['one','two','three'], function(i) {
    return dbQuery('SELECT ' + i);
}).map(function(result) {
    // Individual result
}).map(function(result) {
    // Individual result
}).map(function(result) {
    // Individual result
}).then(function(results) {
    // Now they're back as an array
});

但是上述内容不会与

同时发生
Promise.map(['one','two','three'], function(i) {
    return dbQuery('SELECT ' + i).then(function(result) {
        // Individual result
    }).then(function(result) {
        // Individual result
    }).then(function(result) {
        // Individual result
    })
}).then(function(results) {
    // Now they're back as an array
});

答案 1 :(得分:8)

实际上蓝鸟确实有这个。但它并没有修改数组:Promise.each()

var transformed = []

Promise.map(['one','two','three'], function(i) {
    return dbQuery('SELECT ' + i);
})
.each(function(result) {
    // This is repeating access for each result
    transformed.push(transformResults(result));
})
.then(function(results) {
    // here 'results' is unmodified results from the dbQuery
    // array doesn't get updated by 'each' function
    // here 'transformed' will contain what you did to each above
    return transformed
});

链接地图或在dbQuery上添加更多承诺效果很好,但如果您在触摸单个结果时只需要副作用,each()可能会有优势