Question

我制作了一个简单的GUI，当我运行我的Twitch TV IRC Bot时启动。但是，直到关闭GUI之后，主机器人才会继续运行。如何使脚本与GUI同时运行？这是GUI：

##--GUI--##
def whitelist_wipe():
execfile('command_whitelist_wipe.py')

def modpack():
modpack = modpack_input.get()
return



root = Tk()
modpack_input = StringVar()

root.title('Geekster_Bot')
root.geometry('450x450+500+300')

WhitelistButton = Button(root, text = 'Clear Whitelist!', command + whitelist_wipe).pack()

SubmitButton = Button(root, text = 'Change Modpack', command = modpack).pack()

ModpackName = Entry(root, textvariable=modpack_input).pack()

root.mainloop()

这是从主Bot scrpit启动GUI的部分：

try:
    execfile('GUI.py')

except:
    print('Error loading GUI')

如何在GUI打开的情况下继续使用代码？

修改

GUI.py;

##--GUI--##
def whitelist_wipe():
    execfile('command_whitelist_wipe.py')

def modpack_var():
    modpack_input = modpack_user.get()



root = Tk()
modpack_user = StringVar()

root.title('Geekster_Bot')
root.geometry('350x100+500+300')

Label1 = Label(root, text = 'Geekster_Bot Controls!').pack()

WhitelistButton = Button(root, text = 'Clear Whitelist!', command =whitelist_wipe).pack(side = LEFT)


SubmitButton = Button(root, text = 'Change Modpack', command = modpack_var).pack()

ModpackName = Entry(root, textvariable=modpack_user).pack()

root.mainloop()

Main Bot;

try:
    #Create thread
    gui_thread = threading.Thread( target = execfile, args = ('GUI.py',) )
    #Start thread
    gui_thread.start()
    #Code to run in the main thread

except:
    print('Error loading GUI')

def message(msg): #function for sending messages to the IRC chat
            global queue
            queue = queue + 1
            print queue
            if queue < 20: #ensures does not send >20 msgs per 30 seconds.
                twitch = ('OUTPUT ON ' + channel + ' :' + msg + '\r\n')
                irc.send('PRIVMSG ' + channel + ' :' + msg + '\r\n')
                print (twitch)
            else:
                print 'Message deleted'

def socialtimer(): #function for announcing social every 3 minutes
            global ntimer
            z = open(r'E:\Geekster_Bot\Twitter.txt')
            SOCIAL = z.read()
            message (SOCIAL)
            print 'Social Timers Started!'
            ntimer = threading.Timer(1200,socialtimer)
            ntimer.start()

def queuetimer(): #function for resetting the queue every 30 seconds
            global queue
            print 'queue reset'
            queue = 0
            threading.Timer(30,queuetimer).start()

def modpack_var():
            modpack_input = modpack_user.get()

##--Main Bot--##

#General variables
newsmsg = 'whitelist'
modpack = modpack_input

Answer 1

由于gui本身在一个循环中运行，它会阻止你启动它的线程，直到你停止循环（关闭gui）。你需要在与主要线程不同的线程中启动gui。

您可以使用线程模块执行此操作：

import threading

try:
    #Create thread
    gui_thread = threading.Thread( target = execfile, args = ('GUI.py',) )
    #Start thread
    gui_thread.start()
    #Code to run in the main thread

except:
    print('Error loading GUI')

在此代码中，gui_thread对象是一个线程，它在启动时使用参数execfile运行'GUI.py'可调用（在本例中为函数）。查看线程模块文档以获取更多信息：https://docs.python.org/3.3/library/threading.html

执行文件后继续执行代码 - Python

1 个答案: