Question

我已经编写了一个密码检查程序来检查密码的安全性。有三个功能可以检查安全性并返回值，弱，中等和强。我在这里调用这些函数：

if check_pass_strength_weak(password):
            print "Weak"
        elif check_pass_strength_medium(password):
            print "Medium"
        elif check_pass_strength_strong(password):
            print "Strong""

但强者永远不会归来。这是功能。

def check_pass_strength_strong(password):
    upper_count = 0
    lower_count = 0
    number_count = 0
    for letter in password:
        if letter == letter.upper():
            upper_count = upper_count + 1
        elif letter == letter.lower():
            lower_count = lower_count + 1
        elif letter.isalpha():
            number_count = number_count + 1

    if upper_count > 0 and lower_count > 0 and number_count > 0:
        return True

Answer 1

你的问题在于：

'1' == '1'.upper()

所以elif的其余部分永远不会运行，number_count永远不会增加。翻转它：

if letter.isdigit():
    ...
elif ...

或者，更好的是，实际使用Python str methods，并记住return False：

def check_pass_strength_strong(password):
    upper_count = 0
    lower_count = 0
    number_count = 0
    for letter in password:
        if letter.isdigit():
            number_count += 1
        elif letter.isupper():
            upper_count += 1
        elif letter.islower():
            lower_count += 1
    if upper_count > 0 and lower_count > 0 and number_count > 0:
        return True
    return False

事实上，当您检查多个级别时，您可以将计数分解为：

def count_char_types(password):
    lower_count = upper_count = number_count = 0
    for letter in password:
        if letter.isdigit():
            number_count += 1
        elif letter.isupper():
            upper_count += 1
        elif letter.islower():
            lower_count += 1
    return lower_count, upper_count, number_count

然后实施，例如。

def check_pass_strength_strong(password):
    l, u, n = count_char_types(password)
    return l > 0 and u > 0 and n > 0

并考虑添加symbol_count！

Answer 2

您的代码需要两个修复程序。首先，正如jonrsharpe his answer '1' == '1'.upper()所述，if letter.isdigit(): #... elif #upper/lower conditions所以您不会计算这些数字。您需要先验证这一点：

if check_pass_strength_strong(password):
    print "Strong"
elif check_pass_strength_medium(password):
    print "Mediu"
elif check_pass_strength_weak(password):
    print "Weak"

您可能想要改变密码强度的条件：

{{1}}

Answer 3

使用正则表达式检查数字/大写/小写字符怎么样？

e.g：

def check_pass_strength_strong(password):
    return all((re.findall(r'[A-Z]', password),
                re.findall(r'[a-z]', password),
                re.findall(r'[0-9]', password)))

密码检查器未返回true

3 个答案: