Question

if (isset($_POST["username"]) && isset($_POST["password"])) {
    $adminuser = $_POST["username"];
    $password = $_POST["password"];

    // Connecting to database
    include "../StorageScript/connecttomysql.php";
    //sql query
    $sql = mysql_query("SELECT id FROM admin WHERE username='$adminuser' AND password= '$password' LIMIT 1");

    $existCount = mysql_num_rows($sql);

    while ($row = mysql_fetch_array($sql)) {
        $id = $row["id"];
    }

    $_SESSION['id'] = $id;
    $_SESSION['adminuser'] = $adminuser;
    $_SESSION['password'] = $password;
}

在上面的代码中，我试图从数据库中获取用户ID并将其放入会话变量中。当我尝试在另一个页面中回显$ _SESSION [＆＃39; id＆＃39;]时，它不会显示任何内容。但是，当我尝试回应用户名时，它会起作用。

Answer 1

如果您使用此命令mysql_fetch_array($sql)，请使用$row[0]。

while ($row = mysql_fetch_array($sql)) {
        $id = $row[0];
}

或者如果您想使用$row["id"]，请使用mysql_fetch_assoc($sql)

while ($row = mysql_fetch_assoc($sql)) {
        $id = $row["id"];
}

当然你应该使用mysqli_ *或PDO而不是弃用的mysql_ *函数。

Answer 2

您只需要查询中的一行.. 所以不要使用while循环....

if (isset($_POST["username"]) && isset($_POST["password"])) {
$adminuser = $_POST["username"];
$password = $_POST["password"];

// Connecting to database
include "../StorageScript/connecttomysql.php";
//sql query
$sql = mysql_query("SELECT id FROM admin WHERE username='$adminuser' AND password= '$password' LIMIT 1");

$existCount = mysql_num_rows($sql);
$row = mysql_fetch_array($sql);
$id = $row['id'];
$_SESSION['id'] = $id;
$_SESSION['adminuser'] = $adminuser;
$_SESSION['password'] = $password;

}

mysql_fetch_array（）值不显示

2 个答案: