XAS Parser Android

时间:2014-06-01 13:51:41

标签: java android sax saxparser

无法在下面的代码中找到错误,它正在解析xml,但是字符函数未获取bName和bDescription更新,它总是显示为零,所以我无法在我的设置中设置这些值对象

Java类

/**
 * 
 */
package com.tech.reader.utils;

import java.io.IOException;
import java.io.InputStream;
import java.util.ArrayList;

import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

import com.tech.reader.R;
import com.tech.reader.models.Book;
import com.tech.reader.models.Note;

import android.content.Context;

/**
 * @author hafsalrahman
 * 
 */
public class NoteParser extends DefaultHandler {

    ArrayList<Note> bookL;

    String bookXmlFileName;

    Note bookTmp;
    Boolean bName = false, bDescription = false;
    Context c;

    // SimpleDateFormat sdf= new SimpleDateFormat("yy-MM-dd");

    public NoteParser(Context c, int i) {

        this.bookXmlFileName = fetchFilename(i);
        this.c = c;
        bookL = new ArrayList<Note>();

        parseDocument();

    }

    private String fetchFilename(int i) {
        String s = null;
        if (i == 0) {
            s = "note_" + i + ".xml";
        }
        return s;
    }

    private void parseDocument() {

        // parse

        SAXParserFactory factory = SAXParserFactory.newInstance();

        try {

            SAXParser parser = factory.newSAXParser();
            InputStream is = null;
            // System.out.print(bookXmlFileName);
            try {
                is = c.getResources().openRawResource(R.raw.note1_0);
            } catch (Exception e) {
                System.out.println(e.getMessage() + "no message__");
            }

            if (is != null)
                parser.parse(new InputSource(is), this);

        } catch (ParserConfigurationException e) {

            System.out.println("ParserConfig error");

        } catch (SAXException e) {

            System.out.println("SAXException : xml not well formed");

        } catch (IOException e) {

            System.out.println("IO error");

        }

    }

    public ArrayList<Note> outputDatas() {

        for (Note tmpB : bookL) {

            System.out.println(tmpB.toString());

        }
        return bookL;
    }

    public Object[] outputNames() {

        ArrayList<String> temp = new ArrayList<String>();

        for (Note tmpB : bookL) {

            temp.add(tmpB.getName().toString());

        }
        return temp.toArray();
    }

    @Override
    public void startElement(String uri, String localName, String elementName,
            Attributes attributes) throws SAXException {

        if (elementName.equalsIgnoreCase("Note")) {
            // create a new Employee and put it in Map
            String id = attributes.getValue("id");
            // initialize Employee object and set id attribute
            bookTmp = new Note();
            // bookTmp.setId(id);
            // initialize list
            if (bookL == null)
                bookL = new ArrayList<Note>();
        } else if (elementName.equalsIgnoreCase("name")) {
            // set boolean values for fields, will be used in setting Employee
            // variables
            bName = true;
        } else if (elementName.equalsIgnoreCase("descr")) {
            bDescription = true;
        }
    }

    @Override
    public void endElement(String s, String s1, String element)
            throws SAXException {

        // if end of book element add to list

        if (element.equals("note")) {

            bookL.add(bookTmp);
            // System.out.println("book added" + bookTmp.getId());

        }
    }

    @Override
    public void characters(char[] ac, int i, int j) throws SAXException {

        System.out.println("chars=" + new String(ac, i, j));

        if (bName) {
            // age element, set Employee age
            bookTmp.setName(new String(ac, i, j));
            bName = false;
        } else if (bDescription) {
            bookTmp.setDescription(new String(ac, i, j));
            bDescription = false;
        }

    }

}

要读取的XML

  

<note id="1" >
    <title> Note1
    </title>

    <descr> look at creating applications 
  with XML.
    </descr>
</note>
<note id="2" >
    <title> Note2
    </title>

    <descr> look at creating applications 
  with XML.
    </descr>
</note>
<note id="3" >
    <title> Note3
    </title>

    <descr> look at creating applications 
  with XML. 
    </descr>
</note>
<note id="4" >
    <title> Note4
    </title>

    <descr> look at creating applications 
  with XML.
    </descr>
</note>
<note id="5" >
    <title> Note5
    </title>

    <descr> look at creating applications 
  with XML.
    </descr>
</note>
<note id="6" >
    <title> Note6
    </title>

    <descr> look at creating applications 
  with XML.
    </descr>
</note>
     

1 个答案:

答案 0 :(得分:0)

在字符函数中,无法保证char []数组中的数据已准备就绪或已完成。你应该做的是创建一个StringBuilder并将其累积在characters()中。然后完成后,在endElement()

中处理结果