Question

用户信息不会更新到数据库。这是一个更新用户信息的脚本。用户信息不会更新我得到的错误。＆＃39;你的sql syntaxt中有一个错误WHERE name =＆＃39; jessie＆＃39;限制1

$ u指的是特定人的数据库中的用户名。如果这不是我怎么能做到这一点？因为$ u在我想从数据库中检索数据时有效。

if(isset($_POST['update'])){


echo $name1=$_POST['name'];
$name1=preg_replace('#[^a-z0-9]#i','',$_POST['name']);
$name1=mysql_real_escape_string($_POST['name']);

echo $surname1=$_POST['surname'];
$name1=preg_replace('#[^a-z0-9]#i','',$_POST['surname']);
$name1=mysql_real_escape_string($_POST['surname']);


echo $company_name1=$_POST['company_name'];
$company_name1=preg_replace('#[^a-z0-9]#i','',$_POST['company_name']);
$compnay_name1=mysql_real_escape_string($_POST['company_name']);


echo $tel_number1=$_POST['tel_number'];
$tel_number1=preg_replace('#[^a-z0-9]#i','',$_POST['tel_number']);
$tel_number1=mysql_real_escape_string($_POST['tel_number']);


echo $cell_number1=$_POST['cell_number'];
$cell_number1=preg_replace('#[^a-z0-9]#i','',$_POST['cell_number']);
$cell_number1=mysql_real_escape_string($_POST['cell_number']);


echo $email1=$_POST['email'];
$email1=mysql_real_escape_string($_POST['email']);


echo $location1=$_POST['location'];


echo $main_image1=$_FILES['main_image']['name'];

echo $main_image_tmp=$_FILES['main_image']['tmp_name'];

 $about_us1=$_POST['about_us'];
$about_us=preg_replace('#[^a-z0-9]#i','',$_POST['about_us']);
$about_us=mysql_real_escape_string($_POST['about_us']);

 if($name1==""){

   echo"<script> alert('Please fill in all the fields & make sure word count is less than 80') </script>";

}else{$moveResult=move_uploaded_file($main_image_tmp,"user/$log_username/".$main_image1);
       if($moveResult !=true){
        echo " <script>alert('file upload failed , try again') </script> ";
        exit();

    } else{

 $update_query="UPDATE users_info 
   name='$name1',surname='$surname1',company_name='$company_name1',tel_number='$tel_number1',cell_number='$cell_number1',email='$email1',
   location='$location1',main_image='$main_image1',about_us='$about_us1'
    WHERE  name='$u' LIMIT 1";


if(mysqli_query($connect,$update_query)){

    echo " <script>alert('successfully Posted') </script> ";
        header('location:user.php?u=$log_username');// redirect to users page or just (index.php)

} else{ echo
"<script>alert('Did not work, try again,please post in all the fields) </script> ";
echo mysqli_error($connect);


}

}

}


?>

<?php } ;} else{ echo " you are not logged in "; header("location:login.php");}   ?>

Answer 1

您的查询中缺少

SET 。

$update_query="UPDATE users_info 
SET name='$name1',surname='$surname1',company_name='$company_name1',tel_number='$tel_number1',cell_number='$cell_number1',email='$email1', location='$location1',main_image='$main_image1',about_us='$about_us1' WHERE name='$u' LIMIT 1";

WHERE子句中的SQL语法错误

1 个答案: