Question

我正在尝试在Android中执行建议提供程序。根据我输入的文本（此部分已经完成）显示建议，但是当我想从内容提供程序恢复数据（其_id）时，指令getData（）返回null。

在SuggestionProvider中，我给SUGGEST_COLUMN_TEXT_1，SUGGEST_COLUMN_TEXT_2和SUGGEST_COLUMN_INTENT_DATA_ID赋值：

HashMap<String,String> map = new HashMap<String,String>();
SQLiteQueryBuilder builder = new SQLiteQueryBuilder();
builder.setTables("place");
Map<String, String> projectionMap = new HashMap<String, String>(); 
projectionMap.put(Place.COL_NAME,  Place.COL_NAME+" AS " + SearchManager.SUGGEST_COLUMN_TEXT_1); 
projectionMap.put(Place.COL_ADDRESS,  Place.COL_ADDRESS+" AS " + SearchManager.SUGGEST_COLUMN_TEXT_2); 
projectionMap.put("_id", "_id" + " AS " + SearchManager.SUGGEST_COLUMN_INTENT_DATA_ID); 
projectionMap.put("_id", "_id");  
builder.setProjectionMap(projectionMap);

在SearchableActivity中我使用getDataString（）或getData（）但它们返回null：

private void handleIntent(Intent intent) 
{ 
    if (Intent.ACTION_VIEW.equals(intent.getAction()))  
    { 
        Log.w("test",intent.getDataString()+"a");
    }
    else if (Intent.ACTION_SEARCH.equals(intent.getAction())) 
    { 
        ...
    } 
}

Answer 1

最后，经过尝试，尝试并尝试解决它。

我不知道为什么但是如果我写“projectionMap.put（”_ id“，”_ id“+”AS“+ SearchManager.SUGGEST_COLUMN_INTENT_DATA）”，getData（）返回null但是当我使用“projectionMap.put（ “idPlace”，“idPlace”+“AS”+ SearchManager.SUGGEST_COLUMN_INTENT_DATA）;“getData（）返回我想要的内容。

这是我的最终代码：

SQLiteQueryBuilder builder = new SQLiteQueryBuilder();
builder.setTables("Place");
Map<String, String> projectionMap = new HashMap<String, String>(); 
projectionMap.put(Place.COL_NAME,  Place.COL_NAME+" AS " + SearchManager.SUGGEST_COLUMN_TEXT_1); 
projectionMap.put(Place.COL_ADDRESS,  Place.COL_ADDRESS+" AS " + SearchManager.SUGGEST_COLUMN_TEXT_2); 
projectionMap.put("idPlace",  "idPlace"+" AS " + SearchManager.SUGGEST_COLUMN_INTENT_DATA); 
projectionMap.put("_id", "_id");  
builder.setProjectionMap(projectionMap); 

SQLiteDatabase db = clidbh.getWritableDatabase();

String[] fields = {"idPlace AS _id","name","address","idPlace"};

String where = "name like '%"+selectionArgs[0]+"%'";

row = builder.query(db, fields, where, null, null, null, "_id","3");

if (row == null) {
    return null;
} else if (!row.moveToFirst()) {
    row.close();
return null;
}

getData（）在Suggestion Provider Android中返回null

1 个答案: