Question

我正在使用NodeJs v0.10.28，每当我尝试登录聊天时都会收到错误

TypeError: Object #<Socket> has no method 'set' at Socket.<anonymous>

如果我删除了它的工作线但是没有正常工作。

此代码中的错误是什么

// get the name of the sender
socket.get('nickname', function (err, name) {
  console.log('Chat message by ', name);
  console.log('error ', err);
  sender = name;
});

和

socket.set('nickname', name, function () {
  // this kind of emit will send to all! :D
  io.sockets.emit('chat', {
    msg : "Welcome, " + name + '!', 
    msgr : "Nickname"
  });
});

完整代码

http://pastebin.com/vJx7MYfE

Answer 1

您必须直接在套接字中设置nickname属性！

来自socket.io网站：

旧的io.set（）和io.get（）方法已弃用，仅支持向后兼容。以下是旧授权示例到中间件样式的翻译。

另外，从socket.io网站的一个例子：

// usernames which are currently connected to the chat
var usernames = {};
var numUsers = 0;

    // when the client emits 'add user', this listens and executes
  socket.on('add user', function (username) {
    // we store the username in the socket session for this client
    socket.username = username;
    // add the client's username to the global list
    usernames[username] = username;
    ++numUsers;
    addedUser = true;
    socket.emit('login', {
      numUsers: numUsers
    });
    // echo globally (all clients) that a person has connected
    socket.broadcast.emit('user joined', {
      username: socket.username,
      numUsers: numUsers
    });
  });

查看此处的示例：https://github.com/Automattic/socket.io/blob/master/examples/chat/index.js

Answer 2

与Ludo所说的一样，直接在套接字中设置nickname属性：

// get the name of the sender
var name = socket.nickname;
console.log('Chat message by ', name);
console.log('error ', err);
sender = name;

和

// this kind of emit will send to all! :D
socket.nickname = name;
io.sockets.emit('chat', {
  msg : "Welcome, " + name + '!', 
  msgr : "Nickname"
});

socket.get（）和socket.set（）给出了问题

2 个答案: