我目前正在学习烧瓶。
使用jQuery通过$.ajax()
发送数据后type='post'
,当我检查request.method
时,服务器端会出错。 type='get'
也是如此。
错误
builtins.ValueError
ValueError: View function did not return a response
Traceback (most recent call last)
File "C:\Python33\lib\site-packages\flask\app.py", line 1836, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Python33\lib\site-packages\flask\app.py", line 1820, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "C:\Python33\lib\site-packages\flask\app.py", line 1403, in handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Python33\lib\site-packages\flask\_compat.py", line 33, in reraise
raise value
File "C:\Python33\lib\site-packages\flask\app.py", line 1817, in wsgi_app
response = self.full_dispatch_request()
File "C:\Python33\lib\site-packages\flask\app.py", line 1478, in full_dispatch_request
response = self.make_response(rv)
File "C:\Python33\lib\site-packages\flask\app.py", line 1566, in make_response
raise ValueError('View function did not return a response')
ValueError: View function did not return a response
python代码
if request.method=='psot': #**Error occur when i check**
req = request.get_json()
ck=query_db("select * from users where username=?",[req['u']])
if ck:
if check_password_hash(ck[0]['password'],req['p']):
session['username']=req['u']
return jsonify({'result':'1234'})
else:
return jsonify({'result':'noo'})
else:
return jsonify({'result':'noo'})
jquery的
$.ajax({
type:'post',
contentType: 'application/json',
url:"/login",
data:JSON.stringify({'u':luser.val(),'p':lpass.val()}),
dataType:'json',
success:function(data)
{
if(data.result=='1234')
{
window.location.href='/profile';
}
else
{
$('#log3s').html('username or password not correct').css('color','red');
return false;
}
}
});
答案 0 :(得分:19)
您需要确保使用正确的方法注册视图路径:
@app.route('/login', methods=['GET', 'POST'])
允许GET
和POST
请求,或使用:
@app.route('/login', methods=['POST'])
仅允许 POST
此路线。
要测试请求方法,请使用大写文本进行测试:
if request.method == 'POST':
但请确保始终返回回复。如果request.method
不等于'POST'
,您仍需要返回valid response。