为什么" ==="操作不起作用" filter"或"其中"不适用于我的TableQuery [slick2]

时间:2014-05-31 18:40:00

标签: scala slick slick-2.0

我使用slick 2.0.2和scala,我的数据模型是:

  case class AdItem(id:Option[Long], res:String,status:String,userId:String, head:String,summary:String, url:String, position:String)
class Advertisement(tag:Tag) extends Table[AdItem](tag, "Advertisement"){
  def id=column[Long]("ID", O.PrimaryKey, O.AutoInc)
  def res=column[String]("Resource")
  def status=column[String]("Status")
  def userId=column[String]("User")
  def head=column[String]("head")
  def summary=column[String]("Summary")
  def url=column[String]("Ad_Link")
  def position=column[String]("Position")
  def * = (id.?, res, status, userId,  head, summary, url, position)<>(AdItem.tupled, AdItem.unapply)
  def userFK=foreignKey("Ad_USE_FK", userId, userdata)(_.id)
}

这是My TableQuery:

val addata=TableQuery[Advertisement]

当我执行:

val idd="1232232"
addata.filter(_.id === idd.toLong)

我得到的错误是:

[error] G:\testprojects\slickplay\app\controllers\AdController.scala:30: value =
== is not a member of scala.slick.lifted.Column[Long]
[error]       addata.filter(_.id === idd.toLong)

我遵循http://slick.typesafe.com/doc/2.0.2/queries.html#sorting-and-filtering

的指示

我认为&#34; ===&#34;可以应用列[长]

1 个答案:

答案 0 :(得分:2)

您必须导入正确的隐式转换:

import scala.slick.driver.JdbcDriver.simple._

import scala.slick.driver.TheDriverOfMyChoice.simple._