Question

我有一个代理，我希望代理ajax请求我发现代码并且它运行良好：

(function() {

        if (window.XMLHttpRequest) {

          function parseURI(url) {
            var m = String(url).replace(/^\s+|\s+$/g, "").match(/^([^:\/?#]+:)?(\/\/(?:[^:@]*(?::[^:@]*)?@)?(([^:\/?#]*)(?::(\d*))?))?([^?#]*)(\?[^#]*)?(#[\s\S]*)?/);
            // authority = "//" + user + ":" + pass "@" + hostname + ":" port
            return (m ? {
              href : m[0] || "",
              protocol : m[1] || "",
              authority: m[2] || "",
              host : m[3] || "",
              hostname : m[4] || "",
              port : m[5] || "",
              pathname : m[6] || "",
              search : m[7] || "",
              hash : m[8] || ""
            } : null);
          }

          function rel2abs(base, href) { // RFC 3986

            function removeDotSegments(input) {
              var output = [];
              input.replace(/^(\.\.?(\/|$))+/, "")
                .replace(/\/(\.(\/|$))+/g, "/")
                .replace(/\/\.\.$/, "/../")
                .replace(/\/?[^\/]*/g, function (p) {
                  if (p === "/..") {
                    output.pop();
                  } else {
                    output.push(p);
                  }
                });
              return output.join("").replace(/^\//, input.charAt(0) === "/" ? "/" : "");
            }

            href = parseURI(href || "");
            base = parseURI(base || "");

            return !href || !base ? null : (href.protocol || base.protocol) +
            (href.protocol || href.authority ? href.authority : base.authority) +
            removeDotSegments(href.protocol || href.authority || href.pathname.charAt(0) === "/" ? href.pathname : (href.pathname ? ((base.authority && !base.pathname ? "/" : "") + base.pathname.slice(0, base.pathname.lastIndexOf("/") + 1) + href.pathname) : base.pathname)) +
            (href.protocol || href.authority || href.pathname ? href.search : (href.search || base.search)) +
            href.hash;

          }

          var proxied = window.XMLHttpRequest.prototype.open;
          window.XMLHttpRequest.prototype.open = function() {
              if (arguments[1] !== null && arguments[1] !== undefined) {
                var url = arguments[1];
                url = rel2abs("' . $url . '", url);
                url = "' . PROXY_PREFIX . '" + url;
                arguments[1] = url;
              }
              return proxied.apply(this, [].slice.call(arguments));
          };

        }

      })();

但问题是我还有一些ajax请求，我不需要proxyify，但我也使用XMLHttpRequest ...

问题是我如何过滤ajax个javascript请求并在{{1}}中忽略它们？

Answer 1

添加公共界面以访问代理open电话：

var proxied = window.XMLHttpRequest.prototype.open;
window.XMLHttpRequest.prototype.open_noproxy = proxied;

然后，当您想要进行正常的AJAX调用时，可以调用XMLHttpRequest::open_noproxy()。

另一种方法是在网址中添加关键字，例如NOPROXY:http://whatever。您的替换open功能可以检查网址是否以NOPROXY:开头;如果是这样，它会从URL中删除它，然后在调用proxied之前跳过添加代理前缀的代码。

通过代理过滤ajax请求

1 个答案: