Question

我试图在ruby中递归地比较两个哈希，但是有一些警告。我不能简单地比较字符串，因为一个哈希使用nil而一个使用0等

这是我的功能：

    def compare_yaml(yaml1,yaml2)
    f = ["f", "false", false]
    t = ["t", "true", true]
    nil_equivalents = [0, "", [], {}, nil, " "]
    return true if yaml1 == yaml2

    if (f.include?(yaml1) and f.include?(yaml2)) or (t.include?(yaml1) and t.include?(yaml2))
      return true
    end
    if (nil_equivalents.include?(yaml1) && nil_equivalents.include?(yaml2)) then
        # puts "we found a nil"
    return true
    end
    if (yaml1.class == yaml2.class)
        if yaml1.class.to_s == "Hash"
            puts "gotta hash" + yaml1.to_s
            # a = yaml1.inspect
            # b = yaml2.inspect
            yaml1.keys.map{|k| (yaml2.keys.include? k)? compare_yaml(yaml1[k], yaml2[k]) : false}.reduce{|n,m| n&&m}
        end
        if yaml1.class.to_s == "Array"
            return false unless yaml1.length == yaml2.length
            # yaml1.sort!
            # yaml2.sort!
            return yaml1.zip(yaml2).map { |e| compare_yaml(e[0],e[1])}.reduce{|n,m| n&&m}

        end

    end

return false
end

我尝试使用以下行测试：

compare_yaml({"Computer"=>{"Axiom Tech Co"=>{"Windows 2003"=>[["x86 Family 6 Model 14 Stepping 8 ", nil, 1]]}, "Dell"=>{"Windows 2003"=>[["x86 Family 15 Model 4 Stepping 1 ", nil, 1]]}}, "Desktop"=>{"Hewlett-Packard"=>{"Windows 7 Pro"=>[["Intel Core i7 870 2.93GHz", 1, 1]], "Windows XP Pro"=>[["AMD Athlon Dual Core 4450B", 1, 1]]}}, "Laptop"=>{"Hewlett-Packard"=>{"Windows 7 Pro"=>[["Intel Core i5 M 460 2.53GHz", 1, 1]]}}},{"Computer"=>{"Axiom Tech Co"=>{"Windows 2003"=>[["x86 Family 6 Model 14 Stepping 8", 0, 1]]}, "Dell"=>{"Windows 2003"=>[["x86 Family 15 Model 4 Stepping 1", 0, 1]]}}, "Desktop"=>{"Hewlett Packard"=>{"Windows 7 Pro"=>[["Intel Core i7 870 2.93GHz", 1, 1]], "Windows XP Pro"=>[["AMD Athlon Dual Core 4450B", 1, 1]]}}, "Laptop"=>{"Hewlett Packard"=>{"Windows 7 Pro"=>[["Intel Core i5 M 460 2.53GHz", 1, 1]]}}})

应返回true，但不是

有人可以帮忙吗？

Answer 1

您的样本应该返回false，因为：

"x86 Family 6 Model 14 Stepping 8 " != "x86 Family 6 Model 14 Stepping 8"（第一个末尾有一个空格）
"x86 Family 15 Model 4 Stepping 1 " != "x86 Family 15 Model 4 Stepping 1"（同样的事）
{"Hewlett-Packard"=>{"Windows 7 Pro"=>[["Intel Core i5 M 460 2.53GHz", 1, 1]]}}} != {"Hewlett Packard"=>{"Windows 7 Pro"=>[["Intel Core i7 870 2.93GHz", 1, 1]], "Windows XP Pro"=>[["AMD Athlon Dual Core 4450B", 1, 1]]}}（第一个缺失＆＃34; Windows XP专业版＆＃34;）
"Hewlett Packard" != "Hewlett-Packard"

等等...

底线 - 您的样本应该不返回true ...

比较ruby中的两个复杂哈希值

1 个答案: