在python脚本中接受多个netcat连接

时间:2014-05-30 14:38:32

标签: python netcat

我有一个python脚本来接收netcat发送的字符串。它有效,当我有1个客户端发送字符串,但第二个无法连接。

import socket

HOST = 'localhost'   # use '' to expose to all networks
PORT = 12345

def incoming(host, port):
  """Open specified port and return file-like object"""
  sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
  # set SOL_SOCKET.SO_REUSEADDR=1 to reuse the socket if
  # needed later without waiting for timeout (after it is
  # closed, for example)
  sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
  sock.bind((host, port))
  sock.listen(0)   # do not queue connections
  request, addr = sock.accept()
  return request.makefile('r', 0)
# /-- network ---


for line in incoming(HOST, PORT):
  print line,

我将来自2个客户端的字符串发送到此脚本,但是当第二个客户端开始发送时,连接被中断。 是否可以允许多于1个同时连接?

将sock.listen()更改为更大的数字无效

1 个答案:

答案 0 :(得分:1)

您只接受一个连接。此外,我觉得很奇怪你想要复制文件描述符并像现在一样阅读它。所以,为什么不尝试这样的事情:产生传入的请求并在超时时抛出StopIteration,作为奖励,使用recv代替

import socket

HOST = 'localhost'   # use '' to expose to all networks
PORT = 12345

def incoming(host, port):
    """Open specified port and yield requests"""
    sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
    sock.settimeout(10)
    sock.bind((host, port))
    sock.listen(0)
    try:
        while True:
            request, addr = sock.accept()
            yield request
            request.close()
    except socket.timeout:
        raise StopIteration
    finally:
        sock.close()

for request in incoming(HOST, PORT):
    print request.recv(1024)