Question

我有以下一行

STATUS | webapp | 2014/05/26 15:03:13 | Starting the service...

现在我必须从行中提取小时分钟和秒钟。

我想出了这段代码..

 BufferedReader bin = new BufferedReader(new FileReader(wrapperFile));
 s = bin.readLine();
 final Scanner sc = new Scanner(s);
 final SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");
 while (sc.hasNextLine()) {
        final String line = sc.nextLine();
        final Date date = dateFormat.parse(line);
        final Calendar calendar = Calendar.getInstance();
        calendar.setTime(date);
        System.out.print(calendar.get(Calendar.HOUR));
        System.out.print(calendar.get(Calendar.MINUTE));
        System.out.print(calendar.get(Calendar.SECOND));
 }

但抛出了解析器异常..这个问题是否有解决方法.. ??

Answer 1

([0-9]{2}:){2}[0-9]{2}

将匹配HH：MM：SS

Answer 2

完整的解决方案：

    String input = "STATUS | webapp | 2014/05/26 15:03:13 | Starting the service...";
    String[] splitted = input.split("\\s\\|\\s");
    String dateTime = splitted[2];
    Calendar c = Calendar.getInstance();
    try {
        Date d = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss").parse(dateTime);
        c.setTime(d);
        System.out.println("Year: " + c.get(Calendar.YEAR));
        System.out.println("Month: " + c.get(Calendar.MONTH));
        System.out.println("Day in month: " + c.get(Calendar.DAY_OF_MONTH));
        System.out.println("Hour: " + c.get(Calendar.HOUR_OF_DAY));
        System.out.println("Minute: " + c.get(Calendar.MINUTE));
        System.out.println("Second: " + c.get(Calendar.SECOND));
    }
    catch (Throwable t) {
        // test
        t.printStackTrace();
    }

<强>输出

Year: 2014
Month: 4 // 0-based!
Day in month: 26
Hour: 15
Minute: 3
Second: 13

Answer 3

使用String分隔符拆分输入|，然后在{Lin> rd 数组元素上使用带有模式SimpleDateFormat的{{1}} { {1}}

正则表达式从一行中提取小时分钟

3 个答案: