Question

我有一个字符串，其中||||表示它旁边的目录。 |||表示允许用户访问此目录，||表示分配给这些用户的文件如下。

我需要从此字符串中查找特定用户的已分配文件名。我试图拆分字符串并将值赋给数组，但我无法得到我正在寻找的结果。

这是字符串：

|||| |||根adil001，km11285c，km61052，km61639c，adil001，kl04707c，km47389，km58184，km61052，kq61023c，adil001，km11285c，km61052，km61639c，|| LimitTest_20140528164643.xlsx，testTask2_20140528140033.xlsx，| ||| ||| 1400842226669 adil001，km11285c，km61052，km61639c，adil001，kl04707c，km47389，km58184，km61052，kq61023c，adil001，km11285c，km61052，km61639c，adil001，km11285c，km61052，km61639c，adil001，km11285c，km61052，km61639c ，|| LimitTest_20140528164643.xlsx，testTask2_20140528140033.xlsx，testTask1_20140528135944.xlsx，testTask2_20140528140033.xlsx，|||| ||| 1401191909489 adil001，km11285c，km61052，km61639c，adil001，kl04707c，km47389，km58184，km61052，kq61023c，adil001，km11285c ，km61052，km61639c，adil001，km11285c，km61052，km61639c，adil001，km11285c，km61052，km61639c，adil001，km11285c，km61052，km61639c，adil001，kl04707c，km47389，km58184，km61052，kq61023c，|| LimitTest_20140528164643.xlsx，testTask2_20140528140033.xlsx ，testTask1_20140528135944.xlsx，testTask2_20140528140033.xlsx，LimitTest_20140528164643.xlsx，

这是我的尝试：

function getData() {
    var user = 'km11285c';
    var value = "||||Root|||adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,adil001,km11285c,km61052,km61639c,||LimitTest_20140528164643.xlsx,testTask2_20140528140033.xlsx,||||1400842226669|||adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,||LimitTest_20140528164643.xlsx,testTask2_20140528140033.xlsx,testTask1_20140528135944.xlsx,testTask2_20140528140033.xlsx,||||1401191909489|||adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,||LimitTest_20140528164643.xlsx,testTask2_20140528140033.xlsx,testTask1_20140528135944.xlsx,testTask2_20140528140033.xlsx,LimitTest_20140528164643.xlsx,";
    var users = null;
    var files = null;
    var Dir = value.split("||||");
    var arrayLength = Dir.length;
    for (var i = 0; i < arrayLength; i++) {
        users = Dir[i].split("|||");
    }

    return users;

}

console.log(getData());

和jsFiddle

Answer 1

我改变了你的jsfiddle示例，所以也许你需要在这里和那里更改代码，但这样的事情应该有效：

function buildTree(data) {
    var tree = [];
    var dirs = data.split("||||");
    // Remove the first entry in the array, since it should be empty.
    dirs.splice(0, 1);

    for (var i = 0; i < dirs.length; ++i) {
        var tempArray = dirs[i].split("|||");
        var dirName = tempArray[0];
        var usersAndFiles = tempArray[1];
        tempArray = usersAndFiles.split("||");
        var users = tempArray[0];
        var files = tempArray[1];
        var treeDir = { name: dirName };
        treeDir.users = users.split(",");
        treeDir.files = files.split(",");
        tree.push(treeDir);
    }
    return tree;
}

function getData() {
    var user = 'km11285c';
    var value="||||Root|||adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,adil001,km11285c,km61052,km61639c,||LimitTest_20140528164643.xlsx,testTask2_20140528140033.xlsx,||||1400842226669|||adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,||LimitTest_20140528164643.xlsx,testTask2_20140528140033.xlsx,testTask1_20140528135944.xlsx,testTask2_20140528140033.xlsx,||||1401191909489|||adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,km11285c,km61052,km61639c,adil001,kl04707c,km47389,km58184,km61052,kq61023c,||LimitTest_20140528164643.xlsx,testTask2_20140528140033.xlsx,testTask1_20140528135944.xlsx,testTask2_20140528140033.xlsx,LimitTest_20140528164643.xlsx,";
    var tree = buildTree(value);
    for (var i = 0; i < tree.length; ++i) {
        var dir = tree[i];
        if (dir.users.indexOf(user) >= 0) {
            console.log("User '" + user + "' has access to directory '" + dir.name + "', which contains these files: " + dir.files.join(","));
        }
    }
}

getData();

拆分String并在JavaScript中获取适当的值

1 个答案: