我在下面完成的代码是,每次刷新页面时,它只会对元素进行洗牌。例如:'我演奏钢琴'。我希望它是'我弹钢琴',只有当我点击'争夺'按钮时,它才会随机播放。
thirdChineseSentence.php
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8" />
<title>Sentence Scramble and Sequencer</title>
<link rel="stylesheet" type="text/css" href="Second.css" />
<script src="https://code.jquery.com/jquery-1.10.2.min.js" type="text/javascript">
</script>
<script src="chinesesentence.js" type="text/javascript"></script>
</head>
<body>
<center>
<img src = "http://imageshack.com/a/img842/1461/otd4.jpg"/>
<h1>Hello world</h1>
<?php
// Connect to database server
mysql_connect("localhost", "root", "password") or die (mysql_error ());
// Select database
mysql_select_db("login") or die(mysql_error());
// Get data from the database depending on the value of the id in the URL
$strSQL = "SELECT * FROM sentences WHERE id
ORDER BY RAND() LIMIT 1;";
//create an array with numbers 1-4
$order = array(1,2,3,4);
//shuffle them in random order
shuffle($order);
$rs = mysql_query($strSQL);
// Loop the recordset $rs
while($row = mysql_fetch_array($rs)) {
// Write the data of the person
//Display all the array values from 0-3 (array index starts from 0)
echo "<dt>Sentence:</dt><dd>" . $row[$order[0]] . " " . $row[$order[1]] . " " .
$row[$order[2]] . " " . $row[$order[3]] ."</dd>";
}
// Close the database connection
mysql_close();
?>
<button id="showcontent">Scramble</button>
<div id="content"></div>
</center>
</body>
</html>
chinesesentence.js
$(document).ready(function() {
$('#showcontent').click( function(e) {
e.preventDefault();
url = 'thirdChineseSentence.php';
$.ajax({
type: 'POST',
url: url,
dataType: 'html',
beforeSend: function() {
$( "#content" ).html( "Requesting.." );
},
success: function(html) {
document.getElementById("content").innerHTML=html;
}
});
});
}
答案 0 :(得分:0)
thirdChineseSentence.php可能已被浏览器缓存。设置正确的http标头以使其不被缓存或添加随机参数(例如thirdChineseSentence.php?dummy=42567499823
)以使其每次都刷新。
答案 1 :(得分:0)
您正在向自己发送ajax请求(thirdChineseSentence.php)。
所以首先从thirdChineseSentence.php剪切你的php代码并粘贴新的php文件(server.php)。
现在将您的chinesesentence.js更改为此
$(document).ready(function() {
var url = 'server.php';
$.ajax({
type: 'POST',
url: url,
dataType: 'html',
beforeSend: function() {
$( "#content" ).html( "Requesting.." );
},
success: function(html) {
document.getElementById("content").innerHTML=html;
}
});
$('#showcontent').click( function(e) {
// randomize your code locally here no need to send server request
});
}