Question

嗨我有两张桌子......

有用的表格：

SELECT * FROM 36496839_radioamater.skladovekarty00006;

CISLO    NAME
WO01       one
WO02       four
WO03       tree                  (other cells)

Acctive table

SELECT * FROM 36496839_radioamater.skladovekarty00008;

TEXT                                          NAME
Osvetlenie LED SMARTBAR 3x1,7W WW > WO01        NULL
Osvetlenie LED SMARTBAR 2x1,7W WW > WO02        NULL
Osvetlenie LED SMARTBAR 2x1,7W WW - WO03        NULL                  (other cells)
Osvetlenie LED SMARTBAR 2x1,7W WW / WO04        NULL
Osvetlenie LED SMARTBAR 2x1,7W WW + WO05        NULL

我需要创建一个SQL代码，我可以在table00008中找到行，其中TEXT中有来自table00006的CISLO数据，并通过匹配CISLO＆gt; TEXT

来复制NAME中的值

结果：

TEXT                                          NAME
Osvetlenie LED SMARTBAR 3x1,7W WW WO01        one
Osvetlenie LED SMARTBAR 2x1,7W WW WO02        four
Osvetlenie LED SMARTBAR 2x1,7W WW WO03        tree                  (other cells)
Osvetlenie LED SMARTBAR 2x1,7W WW WO04        NULL
Osvetlenie LED SMARTBAR 2x1,7W WW WO05        NULL

任何人都可以帮助我，我绝望地感谢Thx，Martin

Answer 1

在T-SQL中，您可以编写连接并更新为：

--First check if you get desired results:
Select T1.Text ,T2.CISLO ,T2.Name 
FROM @skladovekarty00008 as T1 
join @skladovekarty00006 as T2 on T1.Text like  N'%' + T2.CISLO + N'%';


--If T2.Name are the values with which you want to replace T1.Name then write as
Update T1
Set T1.Name = T2.Name 
FROM @skladovekarty00008 as T1 
join @skladovekarty00006 as T2 on T1.Text like  N'%' + T2.CISLO + N'%';

Demo.

Answer 2

现在尝试一下这个场景。

UPDATE b  
SET b.NAME = a.NAME  
FROM  
36496839_radioamater.skladovekarty00006 a   
join  
36496839_radioamater.skladovekarty00008 b  
ON a.CISLO = SUBSTRING(REVERSE(b.TEXT),0,CHARINDEX(' ',REVERSE(b.TEXT))-1)

我相信你会加入这两张桌子。如果是这样尝试下面的 [对于表格中的CISLO案例＆＃39; skladovekarty00006＆＃39;可以在TABLE＆＃39; skladovekarty00008＆＃39;]

的TEXT中的任何位置

UPDATE b  
 SET b.NAME = CASE WHEN PATINDEX('%a.CISLO%',b.TEXT) > 0 THEN a.NAME END  
 FROM  
 36496839_radioamater.skladovekarty00006 a  
 join  
 36496839_radioamater.skladovekarty00008 b  
ON a.keycol = b.keycol

fin，copy和paste的SQL代码：

2 个答案: