我一直试图在我的程序中添加一个功能,允许您使用OpenFileDialog选择文件(双击DataGridView单元格时)并将该单元格的值更改为文件的路径选择。我不知道命令是做什么的。我试图猜测,我在网上查了一下,找不到任何东西。
Private Sub dgSound_CellContentClick(sender As Object, e As DataGridViewCellEventArgs) Handles dgSound.CellDoubleClick
If e.ColumnIndex = 3 Then 'Index of "file" column
Dim file As String = ""
OpenFileDialog1.ShowDialog()
file = OpenFileDialog1.FileName
'Contents of cell that was clicked = file
End If
End Sub
答案 0 :(得分:1)
我使用CellClick
而不是CellContentClick
,如下所示......
Private Sub dgSound_CellClick(sender As Object, e As DataGridViewCellEventArgs) Handles dgSound.CellClick
If e.ColumnIndex = 3 Then 'Index of "file" column
Dim file As String = ""
OpenFileDialog1.ShowDialog()
file = OpenFileDialog1.FileName
'Contents of cell that was clicked = file
dgSound.Rows(e.RowIndex).Cells(e.ColumnIndex).Value = file
End If
End Sub