Question

我正在开发Android应用程序，其中应用程序与mysql和php连接。

数据库使用http://10.0.2.2/file.php地址与模拟器完美连接。

但是当我将这个应用程序与我的Android设备连接时，它无法正常工作。

对于Android设备，我使用笔记本电脑的ip-address http://192.168.0.XX/file.php。

我在笔记本电脑中使用ubuntu操作系统。

首先加载活动，填写表单，当我点击提交按钮时，应用程序停止工作并显示一个对话框，显示：

应用无效。你想关闭吗？ 以下代码有什么问题，这是我的android代码：

MainActivity.java

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONObject;

import android.content.Intent;
import android.os.Bundle;
import android.os.StrictMode;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.ViewGroup;
import android.widget.Button;
import android.widget.CheckBox;
import android.widget.EditText;
import android.widget.Toast;
import android.os.Build;

@SuppressLint("NewApi")
public class MainActivity extends ActionBarActivity implements android.view.View.OnClickListener
{
    Button submit,button;
    EditText et1,et2,et3; 
    String url;
    CheckBox c1;
    InputStream is=null;
    String result=null;
    String line=null;
    int code;
    String Uname=null;
    String Email=null;
    String Mobile=null;

    @Override
    protected void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        if (android.os.Build.VERSION.SDK_INT > 9) {
            StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
            StrictMode.setThreadPolicy(policy);
        }

        et1=(EditText)findViewById(R.id.editText1);
        et2=(EditText)findViewById(R.id.editText2);
        et3=(EditText)findViewById(R.id.editText3);
        submit=(Button)findViewById(R.id.button1);
        submit.setOnClickListener(this);
        button=(Button)findViewById(R.id.button2);
        button.setOnClickListener(this);
    }

    @SuppressLint("NewApi")
    @Override
    public void onClick(View v)
    {
        if(v==submit)
        {
            Uname=et1.getText().toString();
            Email=et2.getText().toString();
            Mobile=et3.getText().toString();
            if(Uname.isEmpty() || Uname.length()<0 ||
                    Email.isEmpty() || Email.length()<0 || 
                            Mobile.isEmpty() || Mobile.length()<0 )
            {
                Toast t=Toast.makeText(getApplicationContext(),"Please fill all the fields",Toast.LENGTH_LONG);
                t.show();
            }
            else
            {
                insert();
                Toast.makeText(getBaseContext(), "Password has been sent to your mobile",Toast.LENGTH_SHORT).show();
                et1.setText("");
                et2.setText("");
                et3.setText("");
                Intent i1=new Intent(this,LoginActivity.class);
                startActivity(i1);
            }
        }
        else if(v==button)
        {
            Intent i1=new Intent(this,LoginActivity.class);
            startActivity(i1);
        }


    }

    public void insert() 
    {

        HttpClient httpClient=new DefaultHttpClient();
        HttpPost httpPost=new HttpPost("http://192.168.0.XXX/file.php");

        try             
        {
            ArrayList<NameValuePair>pairs=new ArrayList<NameValuePair>();
            pairs.add(new BasicNameValuePair("Uname", Uname));
            pairs.add(new BasicNameValuePair("Email",Email));
            pairs.add(new BasicNameValuePair("Mobile",Mobile));

            httpPost.setEntity(new UrlEncodedFormEntity(pairs));
            HttpResponse response = httpClient.execute(httpPost); 
            HttpEntity entity = response.getEntity();
            is=entity.getContent();
            Log.e("Success","Connection Success");
        }
        catch(Exception ex)
        {
            Log.e("Failed",ex.toString());          
        }

        try
        {
            BufferedReader r1=new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
            StringBuilder sb=new StringBuilder();
            while((line=r1.readLine())!=null)
            {
                sb.append(line+"\n");
            }
            is.close();
            result=sb.toString();
            Log.e("Result", result);
            Log.e("Success Again", "Connection success-2");
        }
        catch(Exception ex1)
        {
            Log.e("Failed Again...","Unsuccess");
        }

    }
}

Answer 1

如果您正在使用wamp，则可以编辑wamp \ bin \ apache \ apache2.4.9 \ conf \下的httpd.conf文件，将“require local”替换为“require all granted”

Answer 2

我认为你必须检查你的笔记本电脑防火墙或网络限制，如果启用了，那就禁用它们。

Answer 3

将cmd中的ip检查为ipconfig 使用此IP例如“http：\ 192.168.1.1 \ getlist.php”

主要关闭Windows防火墙

无法连接mysql数据库与Android设备

3 个答案: