Question

我一直在使用NSDataDetector来解析字符串中的地址，并且在很大程度上它做得很好。但是在地址'与此类似的情况下，它没有检测到它。

6200 North Evan Blvd Suit 487 Highland UT 84043

目前我正在使用此代码：

NSError *error = nil;
NSDataDetector *detector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeAddress error:&error];


NSArray *matches = [detector matchesInString:output options:0 range:NSMakeRange(0, [output length])];

for (NSTextCheckingResult *match in matches) {
    if ([match resultType] == NSTextCheckingTypeAddress) {

        _address = [_tesseractData substringWithRange:[match range]];
        NSDictionary *data = [match addressComponents];

        _zip = [data objectForKey:@"ZIP"];
        if (_zip) {
            NSRange zipRange = [_tesseractData rangeOfString:_zip];
            if (zipRange.location != NSNotFound) {
                [_tesseractData deleteCharactersInRange:zipRange];
            }
        }

        _city = [data objectForKey:@"City"];
        if (_city) {
            NSRange cityRange = [_tesseractData rangeOfString:[_city uppercaseString]];
            if (cityRange.location != NSNotFound) {
                [_tesseractData deleteCharactersInRange:cityRange];
            }
        }
        _city = [_city capitalizedString];

        _state = [data objectForKey:@"State"];

        _street = [data objectForKey:@"Street"];
        if (_street) {
            NSRange streetRange = [_tesseractData rangeOfString:[_street uppercaseString]];
            if (streetRange.location != NSNotFound) {
                [_tesseractData deleteCharactersInRange:streetRange];
            }
        }
        _street = [_street capitalizedString];

    }
}

有人能建议一种更健壮的方法来解析字符串中的物理地址吗？我需要能够获得Zip，Street，State和City。

Answer 1

NSDataDetector是NSRegularExpression子类，因此您可以创建自定义实例，然后检查Apple将pattern和options参数放在哪里。

这方面的事情：

NSDataDetector * dataDetectorRegEx = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeAddress error:&error];
NSString * dataDetectorPattern = dataDetectorRegEx.pattern;
NSLog(@"Check out this pattern!: %@", dataDetectorPattern);

// Customize the pattern for your special cases
NSString * customPattern = [NSString stringWithFormat:@"<MY_OTHER_PATERNS + %@>", dataDetectorPattern];
NSRegularExpression * customDataDetectorLikeRegEx = [NSRegularExpression regularExpressionWithPattern:customPattern options:someOptions error:&error];

Answer 2

您可以尝试使用正则表达式（RegEx）解析地址信息，我认为这是更健壮的方式。请参阅以下使用RegEx的参考：Making RegEx Easy in Objective-C，Objective {C RegEx类别可在GitHub上获得。

从NSString解析地址而不使用NSDataDetector

2 个答案: