Question

我有一张表如下

cat_id  Cat_Name    Main_Cat_Id

1       veg         null
2       main course 1
3       starter     1
4       Indian      2
5       mexican     2
6       tahi        3
7       chinese     3
8       nonveg      null
9       main course 8
10      indian      9
11      starter     8
12      tahi        11
13      chinese     11

（ Main_Cat_Id 是 cat_id 以前添加的类别）

此表用于产品的类别，其中 veg 类别包含两个子类别主要课程和启动器，其标识为 main_cat_id 那些子类别再次具有印度和墨西哥

的子类别

这种分类取决于用户;他可以为印度，墨西哥添加更多子类别，以便他可以进行任何级别的分类

现在我必须选择任何节点的所有子类别，如果我采取veg我必须选择

(1)veg > (2)main course(1) > (4)indian(2)
                           > (5)mexican(2)
       > (3)starter(1)     > (6)thai(3)
                           > (7)chinese(3)

将字符串形成为1,2,4,5,3,6,7

这样做我写了一个sql函数

CREATE FUNCTION [dbo].[GetSubCategory_TEST]
( @MainCategory int, @Category varchar(max))
RETURNS varchar(max)
AS
BEGIN
    IF EXISTS (SELECT Cat_Id FROM Category WHERE Main_Cat_Id=@MainCategory)
    BEGIN
        DECLARE @TEMP TABLE
        (
            CAT_ID INT
        )
        INSERT INTO @TEMP(CAT_ID) SELECT Cat_Id FROM Category WHERE Main_Cat_Id=@MainCategory
        DECLARE @TEMP_CAT_ID INT
        DECLARE CUR_CAT_ID CURSOR FOR SELECT CAT_ID FROM @TEMP
            OPEN CUR_CAT_ID
            WHILE 1 =1
                BEGIN
                FETCH NEXT FROM CUR_CAT_ID
                INTO  @TEMP_CAT_ID;
                IF @@FETCH_STATUS <> 0
                    SET @Category=@Category+','+ CONVERT(VARCHAR(50), @TEMP_CAT_ID)
                    SET @Category = [dbo].[GetSubCategory](@TEMP_CAT_ID,@Category)
                END
                CLOSE CUR_CAT_ID
                DEALLOCATE CUR_CAT_ID
    END
    return @Category
END

但是这个功能继续执行而没有提供所需的输出我不明白错误发生了什么plz帮助我得到这个

Answer 1

你不需要一个递归函数来构建它，你可以使用Recursive CTE。

像

这样的东西

DECLARE @TABLE TABLE(
    cat_id INT,
    Cat_Name VARCHAR(50),
    Main_Cat_Id INT
)

INSERT INTO @TABLE SELECT 1,'veg',null
INSERT INTO @TABLE SELECT 2,'main course',1
INSERT INTO @TABLE SELECT 3,'starter',1
INSERT INTO @TABLE SELECT 4,'Indian',2
INSERT INTO @TABLE SELECT 5,'mexican',2
INSERT INTO @TABLE SELECT 6,'tahi',3
INSERT INTO @TABLE SELECT 7,'chinese',3
INSERT INTO @TABLE SELECT 8,'nonveg',null
INSERT INTO @TABLE SELECT 9,'main course',8
INSERT INTO @TABLE SELECT 10,'indian',9
INSERT INTO @TABLE SELECT 11,'starter',8
INSERT INTO @TABLE SELECT 12,'tahi',11
INSERT INTO @TABLE SELECT 13,'chinese',11

;WITH Recursives AS (
        SELECT  *,
                CAST(cat_id AS VARCHAR(MAX)) + '\' ID_Path
        FROM    @TABLE
        WHERE   Main_Cat_Id IS NULL
        UNION ALL
        SELECT  t.*,
        r.ID_Path + CAST(t.cat_id AS VARCHAR(MAX)) + '\'
        FROM    @TABLE t INNER JOIN
                Recursives r    ON  t.Main_Cat_Id = r.cat_id
)
SELECT  *
FROM    Recursives

Answer 2

我很惭愧，但是我用@astander scipt给出了字符串结果。

首先，我创建了您提供的数据。其次，我收集了我需要的行然后使用XML我将所有内容放在一行中（函数STUFF删除第一个逗号）

DECLARE @TABLE TABLE(
    cat_id INT,
    Cat_Name VARCHAR(50),
    Main_Cat_Id INT
)

DECLARE @Collected TABLE(
    cat_id INT
)

INSERT INTO @TABLE SELECT 1,'veg',null
INSERT INTO @TABLE SELECT 2,'main course',1
INSERT INTO @TABLE SELECT 3,'starter',1
INSERT INTO @TABLE SELECT 4,'Indian',2
INSERT INTO @TABLE SELECT 5,'mexican',2
INSERT INTO @TABLE SELECT 6,'tahi',3
INSERT INTO @TABLE SELECT 7,'chinese',3
INSERT INTO @TABLE SELECT 8,'nonveg',null
INSERT INTO @TABLE SELECT 9,'main course',8
INSERT INTO @TABLE SELECT 10,'indian',9
INSERT INTO @TABLE SELECT 11,'starter',8
INSERT INTO @TABLE SELECT 12,'tahi',11
INSERT INTO @TABLE SELECT 13,'chinese',11
INSERT INTO @TABLE SELECT 14,'chinese',6

DECLARE @nodeID INT = 1;
DECLARE @result VARCHAR(MAX);

;WITH Recursives AS (
        SELECT cat_id, main_cat_id
        FROM @TABLE
        WHERE Cat_Id = @nodeID
        UNION ALL
        SELECT T.cat_id, T.main_cat_id
        FROM @TABLE AS T 
        INNER JOIN Recursives AS R 
            ON  t.Main_Cat_Id = r.cat_id
)
INSERT INTO @Collected
SELECT cat_id
FROM Recursives


SELECT @result = STUFF(
        (SELECT ',' + CAST( cat_id AS VARCHAR)
        FROM @Collected
        ORDER BY cat_id
        FOR XML PATH('')
        ), 1,1,'')

SELECT @result

如何在sql server中调用递归函数

2 个答案: