如何使用project / Build.scala生成java playproject?

时间:2014-05-28 11:02:44

标签: java build sbt playframework-2.2

我使用playframework2.2:尝试构建一个游戏支持项目。

在我的Build.scala中,我想添加play.Project.playJavaSetting:

val main = play.Project(appName, appVersion, appDependencies)
.settings(play.Project.playJavaSettings)   //error here
.settings(
    resolvers += "webjars" at "http://webjars.github.com/m2",
    resolvers += "typesafe" at "http://repo.typesafe.com/typesafe/release" 
)

错误是:

[error] F:\git\play-example-form\project\Build.scala:19: overloaded method value
settings with alternatives:
[error]   (ss: sbt.Def.Setting[_]*)sbt.Project <and>
[error]   => Seq[sbt.Def.Setting[_]]
[error]  cannot be applied to (Seq[sbt.Setting[_]])
[error]         .settings(play.Project.playJavaSettings)
[error]          ^

如果我不添加playJavaSetting,它会给我错误的收集申请错误,我的意思是:

    val main = play.Project(appName, appVersion, appDependencies)
//.settings(play.Project.playJavaSettings)   

,错误是:

[error]   required: play.api.data.Form<StudentFormData>,scala.collection.immutab
le.Map<String,Object>,scala.collection.immutable.List<String>,scala.collection.i
mmutable.Map<String,Object>,scala.collection.immutable.Map<String,Object>
[error]   found: play.data.Form<StudentFormData>,java.util.Map<String,Boolean>,j
ava.util.List<String>,java.util.Map<String,Boolean>,java.util.Map<String,Boolean

你可以看到框架应用了scala.collection.immutable.List而不是play.util.List,如果我真的想应用java集合如何在Build.scala文件中设置环境设置?

1 个答案:

答案 0 :(得分:2)

你应该改变

.settings(play.Project.playJavaSettings)

.settings(play.Project.playJavaSettings:_ *)

settings方法声明为def settings(ss: Setting[_]*),这意味着它需要重复Setting[_]类型的参数。 play.Project.playJavaSettings的类型为Seq[Setting[_]]。要将一个转换为另一个,Scala有一个特殊的类型注释。

如果您对详细信息感兴趣,请检查The Scala Language Specification

4.6.2重复参数