Question

我有2张桌子，我们在团结时会遇到问题告诉那个

表1

 Customer | Buyer | Usage | Item Code | Item Name | Month1 | Month2 

   A      Jirulu  Bottom    111111     Item1        100      50          
   B      Bakeyo  Top       122222     Item2        100      50        
   D      Sagero  Bottom    133333     Item3        100      50

表2

Customer | Buyer | Usage | Item Code | Item Name | Month3 | Month4 | 

   A      Jirulu  Bottom    111111     Item1        100      50      
   C      Bakeyo  Top       122222     Item2        100      50      
   D      Sagero  Bottom    133333     Item3        100      50

我怎样才能得到这样的结果：

Customer | Buyer | Usage | Item Code | Item Name | Month1 | Month2| Month3 | Month4 | 

   A      Jirulu  Bottom    111111     Item1        100      50      100      50    
   B      Bakeyo  Top       122222     Item2        100      50      100      50        
   C      Bakeyo  Top       122222     Item2         0        0      100      50
   D      Sagero  Bottom    133333     Item3        100      50      100      50

请建议，谢谢你！

Answer 1

以下查询将为您提供帮助。

SELECT tab.customer, 
       tab.buyer, 
       tab.usage, 
       tab.usage, 
       tab.itemcode, 
       tab.itemname, 
       Sum(month1) AS Month1, 
       Sum(month2) AS Month2, 
       Sum(month3) AS Month3, 
       Sum(month4) AS Month4 
FROM   (SELECT customer, 
           buyer, 
           usage, 
           itemcode, 
           itemname, 
           month1, 
           month2, 
           0 AS month3, 
           0 AS month4 
    FROM   table1 
    UNION ALL 
    SELECT customer, 
           buyer, 
           usage, 
           itemcode, 
           itemname, 
           0 AS month1, 
           0 AS month2, 
           month3, 
           month4 
    FROM   table2) tab 
GROUP  BY tab.customer, 
      tab.buyer, 
      tab.usage, 
      tab.usage, 
      tab.itemcode, 
      tab.itemname

Answer 2

除UNION之外已经显示JOIN这两个表的情况，在这种情况下，在两个表格中有不同的客户a FULL JOIN

SELECT Coalesce(t1.[Customer], t2.[Customer]) [Customer]
     , Coalesce(t1.[Buyer], t2.[Buyer]) [Buyer]
     , Coalesce(t1.[Usage], t2.[Usage]) [Usage]
     , Coalesce(t1.[Item Code], t2.[Item Code]) [Item Code]
     , Coalesce(t1.[Item Name], t2.[Item Name]) [Item Name]
     , Coalesce([Month1], 0) [Month1]
     , Coalesce([Month2], 0) [Month2]
     , Coalesce([Month3], 0) [Month3]
     , Coalesce([Month4], 0) [Month4]
FROM   Table1 t1
       FULL JOIN Table2 t2 ON t1.Customer = t2.Customer 
                          and t1.Buyer = t2.Buyer 
                          and t1.[usage] = t2.[usage]
                          and t1.[Item Code] = t2.[Item Code]
                          and t1.[Item Name] = t2.[Item Name]
ORDER BY Coalesce(t1.[Customer], t2.[Customer])

另一方面，如果你有垂直分区，如果你创建一个加入更短的分区的密钥，它会好很多，例如你可以划分密钥部分并添加一个假的ID来关联另一个分区，比如

ID | Customer | Buyer | Usage | Item Code | Item Name

ID | Month1 | Month2

ID | Month3 | Month4

SQL Compare和Unity表

2 个答案: