Question

我有两个函数，它们都在我的php文件上执行单独的GET调用。我正在尝试做一个$。 GET调用执行不同的任务

每当我试图得到404错误时，我就会更改此变量。

 var url = "output-tv.php";

这是我的函数，如果它有404错误则会发出警告

 $.ajax({
   url: url,
   statusCode:{
   404: function(){
   alert('Page not found');
 }
},          
 success: function(data){
   alert('success');    
   }
});

这是我创建表的函数

 $.get(url,
  {tv_type:tv_type,screen_size:screen_size,connectivity:connectivity,features:features},
  function(response)
  {

  var i = 0;
  var table = document.getElementById("table")
  var row = table.insertRow(0);
  $( ".result" ).html( statusCode );
  alert( "Load was performed." );

 $("#table td").remove();
 $(response.result).each(function () {
 var rowString = "<tr>";
 rowString += "<td>" + this.product_code + "</td>
 rowString += "<td>" + this.tv_name + "</td>";
 rowString += "<td>" + this.size + "</td>";
 rowString += "<td>" + this.tv_type + "</td>";
 rowString += "</tr>";
 $('#table').append(rowString);
 });

我尝试过这样做，但我无法捕捉404错误。

 $.get(url,
 {tv_type:tv_type,screen_size:screen_size,connectivity:connectivity,features:features},
 function(response, statusCode){

$(.result){
 statusCode:{
   404: function(){
   alert('Page not found');
 }
},          
 success: function(data){
   alert('success');
 }

 $("#table td").remove();
 $(response.result).each(function () {
 var rowString = "<tr>";
 rowString += "<td>" + this.product_code + "</td>";
 rowString += "<td>" + this.tv_name + "</td>";
 rowString += "<td>" + this.size + "</td>";
 rowString += "<td>" + this.tv_type + "</td>";
 rowString += "</tr>";
 $('#table').append(rowString);
 });

 }, "json" );

Answer 1

成功与失败，你必须使用完整版：

complete: function(xhr, data) {
        if (xhr.status == 404)
            // do something
        else
            //do something else
    }

$ .get是否可以提醒http状态代码并同时创建表？

1 个答案: