Question

我们在ms sql server中有datediff（）。我希望在两天之间找到“工作”日（周日除外）。例如如果我使用datediff（day，'2014-05-01'，'2014-05-31'）那么它应该给出除星期日之外的日数

有没有办法做到这一点？

Answer 1

试试这个！

declare @d1 datetime,@d2 datetime
set @d1='2014-05-04'
set @d2='2014-05-18'

SELECT
   (DATEDIFF(dd, @d1, @d2) + 1)
  -(DATEDIFF(wk, @d1, @d2))
  -(CASE WHEN DATENAME(dw, @d2) = 'Sunday' THEN 1 ELSE 0 END) -- discard sundays

DEMO

Answer 2

我想这个可以正常工作：

SET DATEFIRST 1;
DECLARE @StartDate DATE = '2014-05-01',
        @EndDate DATE = '2014-05-31';
DECLARE @RenamingDays INT = DATEDIFF(D,@StartDate,DATEADD(DAY,1,@EndDate)) % 7;
DECLARE @NoOfWeeks INT = DATEDIFF(D,@StartDate,DATEADD(DAY,1,@EndDate)) / 7;

;with cte as
(
    SELECT @EndDate Dates,
           0 i
    WHERE @RenamingDays > 0

    UNION ALL

    SELECT DATEADD(DAY, -1, Dates),
           i + 1
    FROM CTE
    WHERE i + 1 < @RenamingDays
)
,WorkingDays AS
(
    SELECT COUNT(Dates) RenamingWorkingDays
    FROM cte
    WHERE DATEPART(dw, Dates) != 7
)
SELECT @NoOfWeeks * 6 + RenamingWorkingDays
FROM WorkingDays

在ms sql server中找不到工作日，不包括星期日

2 个答案: