应用程序脚本错误请先选择活动工作表。 （第4行，文件“代码”）

Question

我在尝试根据this教程发布我的应用脚本信息中心应用时收到错误Please select an active sheet first. (line 4, file "Code")。我已经阅读了一些关于设置活动工作表的其他帖子，但它只会产生更多错误。我不知道如何纠正这个问题。有人可以告诉我我做错了吗？

function doGet() {
  var ss = SpreadsheetApp.openById('<sheetid>');
  var data = ss.getDataRange();

  var ageFilter = Charts.newNumberRangeFilter().setFilterColumnIndex(1).build();
  var nameFilter = Charts.newStringFilter().setFilterColumnIndex(0).build();
  var genderFilter = Charts.newStringFilter().setFilterColumnIndex(2).build();

  var tableChart = Charts.newTableChart()
                   .setDataViewDefinition(Charts.newDataViewDefinition().set([0,1,2]))
                   .build();

  var pieChart = Charts.newPieChart()
                   .setDataViewDefinition(Charts.newDataViewDefinition().set([0,,2]))
                   .build();

  var dashboard = Charts.newDashboardPanel().setDataTable(data)
                   .bind([ageFilter,nameFilter,genderFilter], [tableChart, pieChart])
                   .build();

  var app = UiApp.createApplication();
  var filterPanel = app.createVerticalPanel();
  var chartPanel = app.createHorizontalPanel();
  filterPanel.add(ageFilter).add(nameFilter).add(genderFilter).setSpacing(10);
  chartPanel.add(tableChart).add(pieChart).setSpacing(10);

  dashboard.add(app.createVerticalPanel().add(filterPanel).add(chartPanel));
  app.add(dashboard);
  return app;
}

Answer 1

var ss = SpreadsheetApp.openById('<sheetid>');
var sheet = ss.getSheetByName('sheetNameHere');///////Need to get the sheet, not just the whole work book.
var data = sheet.getDataRange();