Question

我是php，mysql和javascript的新手。最近我一直在为每个按钮创建一个弹出窗口。当我将代码放在表单标记中时，代码可以正常工作，但它是添加和删除的常规弹出窗口。我想要一个确认弹出窗口来添加和删除。我尝试将代码放在输入标签上，但代码没有运行。我做错了什么？

HTML

<form action="da.php" method="post">
name:<input type="text" name="input1">
<br/>
<input onSubmit="if(!confirm('Submit?')){return false;}" name="add1" type="submit" value="Submit" />
<input onSubmit="if(!confirm('Delete?')){return false;}" name="del1" type="submit" value="Delete" /> 

</form>
</body>

PHP

define('db_name', 'demo');
define('db_user', 'root');
define('db_password', 'pw');
define('db_host', 'localhost');

$link = mysql_connect (db_host, db_user, db_password);

if (!$link) {
die('could not connect: '. mysql_error());
}

$db_selected = mysql_select_db(db_name, $link);

if (!$db_selected) {
die('can\'t use' . db_name . ': ' . mysql_error());
}


$value = $_POST['input1'];



if (isset($_POST['add1'])) {
$sql = "insert into demo (name) values ('$value')";

if (!mysql_query($sql)) {
    die('Error: ' . mysql_error());
}

}

elseif (isset($_POST['del1'])) {
$sql = "delete from demo where name = ('$value')";

if (!mysql_query($sql)) {
  die('Error: ' . mysql_error());
}

}



mysql_close();

header( 'Location:  localhost://da-form.html') ;

?>

Answer 1

您可以在javascript中使用window.confirm来获取用户的确认。 http://www.w3schools.com/jsref/met_win_confirm.asp

Answer 2

尝试onclick而不是onSubmit

onSubmit通常用于表单标记

Answer 3

试试这个

<form action="da.php" method="post">
name:<input type="text" name="input1">
<br/>
<input onClick="return confirm('Submit?');" name="add1" type="submit" value="Submit" />
<input onClick="return confirm('Delete?');" name="del1" type="submit" value="Delete" /> 

</form>

两个提交按钮的Javascript弹出确认

3 个答案: