如何使用python查找文本文件中的行数？

Question

1. 我需要获取给定.tst文件的文本文件...并找到其中的行数
2. 我的输出为0 ..
3. 我需要执行两次程序以获取这些文本文件
4. 我的代码有问题吗？

name_of_file = raw_input("tst file address please:")

import re
f = open(name_of_file+".tst",'r')
data = f.read()
y = re.findall(r'Test Case:(.*?)TEST.UNIT:',data,re.DOTALL)
fb = open('tcases.txt' ,'w' )
for line in y :
 fb.write(line)
z = re.findall(r'TEST.SUBPROGRAM:(.*?)TEST.NEW',data,re.DOTALL)
fc = open('tsubprgs.txt' ,'w' )
for line in z :
 fc.write(line)
x = re.findall(r'TEST.UNIT:(.*?)TEST.SUBPROGRAM:',data,re.DOTALL)
fa = open('tunits.txt' ,'w' )
for line in x :
 fa.write(line)

with open('tunits.txt') as foo:
 lines = len(foo.readlines())
 print lines

Answer 1

试试这个

with open(<pathtofile>) as f:
      print len(f.readlines())

Answer 2

在您的示例中，re.findall()返回一个列表，您可以在不重新打开和计算结果文件的情况下获取匹配数，例如：

x = re.findall(r'TEST.UNIT:(.*?)TEST.SUBPROGRAM:',data,re.DOTALL)
num_tunits = len(x)

请参阅other answers了解文件行计数的想法。

Answer 3

myfile = "names.txt"

num_names = 0

with open(myfile, 'r') as f:
    for line in f:
    names = line.split()

    num_names += len(names)

print (num_names)