Question

我有四个不同的名单。 headers，descriptions，short_descriptions和misc。我想将这些结合到所有可能的打印方式中：

header\n
description\n
short_description\n
misc

就好像我曾经（因为显而易见的原因，我在这个例子中跳过short_description和misc）

headers = ['Hello there', 'Hi there!']
description = ['I like pie', 'Ho ho ho']
...

我希望它打印出来像：

Hello there
I like pie
...

Hello there
Ho ho ho
...

Hi there!
I like pie
...

Hi there!
Ho ho ho
...

你认为最好/最干净/最有效的方法是什么？是for - 筑巢唯一的方法吗？

Answer 1

这是你要找的吗？ http://docs.python.org/library/itertools.html#itertools.product

Answer 2

import itertools

headers = ['Hello there', 'Hi there!']
description = ['I like pie', 'Ho ho ho']

for p in itertools.product(headers,description):
    print('\n'.join(p)+'\n')

Answer 3

要执行此操作的生成器表达式：

for h, d in ((h,d) for h in headers for d in description):
    print h
    print d

Answer 4

查看 itertools 模块，它包含从任何迭代中获取组合和排列的函数。

Answer 5

>>> h = 'h1 h2 h3'.split()
>>> h
['h1', 'h2', 'h3']
>>> d = 'd1 d2'.split()
>>> s = 's1 s2 s3'.split()
>>> lists = [h, d, s]
>>> from itertools import product
>>> for hds in product(*lists):
    print(', '.join(hds))

h1, d1, s1
h1, d1, s2
h1, d1, s3
h1, d2, s1
h1, d2, s2
h1, d2, s3
h2, d1, s1
h2, d1, s2
h2, d1, s3
h2, d2, s1
h2, d2, s2
h2, d2, s3
h3, d1, s1
h3, d1, s2
h3, d1, s3
h3, d2, s1
h3, d2, s2
h3, d2, s3
>>>

在Python中创建四个列表的所有可能组合的最有效方法？

5 个答案: