Question

我的控制器中有两个功能，如下所示。

$scope.formatPaymentDates = function() {
  $scope.formatDate($scope.payment.due_date);

  $scope.formatDate($scope.payment.date);
};


$scope.formatDate = function(attr) {
  if (attr) {
    var split_date = attr.split("-");

    if (split_date[0].length == 4) {
      attr = split_date[1] + "-" + split_date[2] + "-" + split_date[0];
    }  else {
      attr = split_date[2] + "-" + split_date[0] + "-" + split_date[1];
    }
  }
};

问题是函数formatDate只设置范围变量属性而不保存它。我错过了什么？

Answer 1

在JavaScript中，字符串和数字按值传递，而对象则通过引用传递。您应该传递一个对象作为参数。

或者，正如@faby提到的那样，返回值：

$scope.formatPaymentDates = function() {
  $scope.payment.due_date = $scope.formatDate($scope.payment.due_date);
  $scope.payment.date = $scope.formatDate($scope.payment.date);
};


$scope.formatDate = function(attr) {
  var result;
  if (attr) {
    var split_date = attr.split("-");

    if (split_date[0].length == 4) {
      result = split_date[1] + "-" + split_date[2] + "-" + split_date[0];
    }  else {
      result = split_date[2] + "-" + split_date[0] + "-" + split_date[1];
    }
  }
  return result;
};

Answer 2

问题是您没有从formatDate函数返回任何结果。您正在操作函数内部的变量，然后销毁它。

试试这个

    $scope.formatDate = function(attr) {
      if (attr) {
        var split_date = attr.split("-");

        if (split_date[0].length == 4) {
          attr = split_date[1] + "-" + split_date[2] + "-" + split_date[0];
        }  else {
          attr = split_date[2] + "-" + split_date[0] + "-" + split_date[1];
        }
    return attr;
      }
return null
    };

然后

$scope.formatPaymentDates = function() {
  $scope.payment.due_date= $scope.formatDate($scope.payment.due_date);

  $scope.payment.date=$scope.formatDate($scope.payment.date);
};

将作为参数的范围传递给要保存的函数

2 个答案: