我在C#中有以下几行代码:
internal static object AssignMatchingPropertyValues(object sourceObject, object targetObject)
{
Type sourceType = sourceObject.GetType();
PropertyInfo[] sourcePropertyInfos = sourceType.GetProperties(BindingFlags.Public | BindingFlags.Instance);
foreach (var sourcePropertyInfo in sourcePropertyInfos)
{
var targetPropertyInfo = targetObject.GetType().GetProperty(sourcePropertyInfo.Name);
if (targetPropertyInfo != null)
{
targetPropertyInfo.SetValue(targetObject, sourcePropertyInfo.GetValue(sourceObject, null), null);
}
}
return targetObject;
}
我想在F#中实现功能等同,所以我做了类似的事情:
member this.AssignMatchingPropertyValues(sourceObject, targetObject)=
let sourceType = sourceObject.GetType()
let sourcePropertyInfos = sourceType.GetProperties(BindingFlags.Instance)
let assignedProperities = sourcePropertyInfos
|> Seq.map(fun spi -> spi, targetObject.GetType().GetProperty(spi.Name))
|> Seq.map(fun (spi,tpi) -> tpi.SetValue(targetObject, spi.GetValue(sourceObject,null),null))
()
问题在于它不起作用。我认为b / c的不变性,我正在收集一个新的集合。有没有办法引用原始集合?这是解决这个问题的正确途径吗?
答案 0 :(得分:4)
以下是您的C#的直接翻译,您的F#代码不是:
let AssignMatchingPropertyValues sourceObject targetObject =
let sourceType = sourceObject.GetType()
let targetType = targetObject.GetType()
let sourcePropertyInfos = sourceType.GetProperties(BindingFlags.Public ||| BindingFlags.Instance)
for sourcePropertyInfo in sourcePropertyInfos do
match targetType.GetProperty(sourcePropertyInfo.Name) with
| null -> ()
| targetPropertyInfo -> targetPropertyInfo.SetValue(targetObject, sourcePropertyInfo.GetValue(sourceObject, null), null)
targetObject
答案 1 :(得分:3)
Seq.map
很懒,你不会在任何地方进行评估。您可以使用Seq.iter
:
sourcePropertyInfos
|> Seq.map(fun spi -> spi, targetObject.GetType().GetProperty(spi.Name))
|> Seq.iter(fun (spi,tpi) -> tpi.SetValue(targetObject, spi.GetValue(sourceObject,null),null))