Question

有人可以帮助我如何在我的while循环中获取我的MySQL列名吗？我的代码是这样的：

if (mysqli_connect_errno()) {
    echo "MySQL failed: " . mysqli_connect_errno();
}

if (isset($_GET['date'])) {
    $get_date = $_GET['date'];
    $result = mysqli_query($conn, "SELECT * FROM stats WHERE form_date = '$get_date'");
    $col = array();
    while ($row = mysqli_fetch_array($result)) {
        $col[] = $row['year'];
        $col[] = $row['month'];
        $col[] = $row['day'];
        $col[] = $row['weekday'];
        $col[] = $row['form_date'];
        $col[] = $row['name'];
        $col[] = $row['count'];
        $col[] = $row['lang'];
    }
    echo "<pre>";
    print_r($col);
    echo "</pre>";
    mysqli_close($conn);
} else {
    echo "Please set a date value in URL parameter ?date=[YYYY-MM-DD]";
}

我返回的数组看起来像这样：

Array
(
    [0] => 2014
    [1] => 01
    [2] => 01
    [3] => Wednesday
    [4] => 2014-01-01
    [5] => Michael K
    [6] => 41
    [7] => SE
    [8] => 2014
    [9] => 01
    [10] => 01
    [11] => Wednesday
    [12] => 2014-01-01
    [13] => Nicklas S
    [14] => 40
    [15] => DK
    [16] => 2014
    [17] => 01
    [18] => 01
    [19] => Wednesday
    [20] => 2014-01-01
    [21] => Jesper S
    [22] => 5
    [23] => SE
)

但是我想让我的数组像这样返回：

Array
(
    [year] => 2014
    [day] => 01
    [month] => 01
    [weekday] => Wednesday
    [form_date] => 2014-01-01
    [name] => Michael K
    [count] => 41
    [lang] => SE
    [year] => 2014
    [month] => 01
    [day] => 01
    [weekday] => Wednesday
    [form_date] => 2014-01-01
    [name] => Nicklas S
    [count] => 40
    [lang] => DK
    [year] => 2014
    [month] => 01
    [day] => 01
    [weekday] => Wednesday
    [form_date] => 2014-01-01
    [name] => Jesper S
    [count] => 5
    [lang] => SE
)

因此，我的数组中的键与我在数据库中的列名相匹配。我似乎无法理解我是如何做到这一点的。有人可以帮忙吗？： - ）

Answer 1

更改

$col = array();
while ($row = mysqli_fetch_array($result)) {
    $col[] = $row['year'];
    $col[] = $row['month'];
    $col[] = $row['day'];
    $col[] = $row['weekday'];
    $col[] = $row['form_date'];
    $col[] = $row['name'];
    $col[] = $row['count'];
    $col[] = $row['lang'];
}

到

$col = array();
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
    $col[] = $row;
}

print_r($col);

mysql_fetch_array()有第二个论点。此可选参数是一个常量，指示应从当前行数据生成哪种类型的数组。此参数的可能值是常量MYSQLI_ASSOC，MYSQLI_NUM或MYSQLI_BOTH。

Answer 2

您正在寻找mysqli_fetch_assoc()，它将结果作为关联数组（column =＆gt; value）。

然后试试这个：

while ($row = mysqli_fetch_assoc($result)) {
    echo "<pre>";
    print_r($row);
    echo "</pre>";
}

Answer 3

您不能使用这样的关联数组，因为它将具有重复的键索引，这是不允许的。我建议你使用重组数组来让每个＆＃34;组＆＃34;键作为嵌套数组。

Answer 4

使用mysql_assoc_array()代替mysq_fetch_array()

在PHP数组中获取MySQL列名

4 个答案: