Question

我在mysql中有表，如下面的

表格数据

   id        items     color        date
    1          22       blue      2014-05-25
    2         344       yellow    2014-05-26
    3         255       blue      2014-05-26
    4         234       blue      2014-05-26
    5         200       yellow    2014-05-27
    6         100       blue      2014-05-27
    7         100       yellow    2014-05-25
    8         233       blue      2014-05-26

我需要基于颜色的项目总和，按日期分组...

喜欢

我需要这样的输出：

Date        Items    blue  yellow
2014-05-25    122      22   100
2014-05-26   1066     722   344
2014-05-27    300     100   200

我需要Mysql Query来获取上面给出的输出..

Answer 1

您可以按日期进行正常分组并根据http://dev.mysql.com/doc/refman/5.0/en/case.html 你应该

select Date, sum(items) as Items, 
sum(case when color = 'blue' then color else 0 end case) as blue,
sum(case when color = 'yellow' then color else 0 end case) as yellow
from ...
group by Date

很抱歉，如果语法不匹配。我不做MySQL。

Answer 2

你可以这样做：

SELECT
    Table1.Date,
    SUM(CASE WHEN Table1.color='blue' THEN Table1.items ELSE 0 END) AS blue,
    SUM(CASE WHEN Table1.color='yellow' THEN Table1.items ELSE 0 END) AS yellow,
    SUM(Table1.items) AS Items
FROM
    Table1
GROUP BY
    Table1.Date

Answer 3

试试这个..

SELECT date, sum(items), sum(if(color='blue',items,0)) as blue, sum(if(color='yellow',items,0)) as yellow
FROM `Table`
GROUP BY date
ORDER BY date ASC

mysql中具有列类别的行的SUM

3 个答案: