Question

我正在开发一个有登录页面的应用程序。如果用户成功登录，则“登录”按钮将更改为“注销”。为此我使用login.setText("Logout");。但是我想为这个按钮改变动作。这意味着如果用户在登录文本更改之前单击登录，则页面将重定向到登录页面。我不知道如何在按钮文本更改后更改操作。请给我一些线索......

Answer 1

// Try this way,hope this will help you to solve your problem...

        btnLoginLogout.setText("Login");
        btnLoginLogout.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                if(((Button)v).getText().equals("Login")){
                    ((Button)v).setText("Logout");
                    // do your login code here
                }else{
                    ((Button)v).setText("Login");
                    // do your login code here
                }
            }
        });

Answer 2

您可以尝试这样的事情：

public class Test extends Activity implements View.OnClickListener{

    private boolean isLogin = true;
    private static final String TEXT_LOGIN = "Login", TEXT_LOGOUT = "Logout";

    @Override
    protected void onCreate (Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        setContentView(R.layout.your_lauyout);

        final Button btnLoginLogout = (Button) findViewById(R.id.btn_login_logout);
        // Initialize the button with Login text
        btnLoginLogout.setText(TEXT_LOGIN);
        // Set the click listener for the button
        btnLoginLogout.setOnClickListener(this);
    }

    @Override
    public void onClick (View v) {
        switch (v.getId()){
            case R.id.btn_login_logout:
                if (isLogin) {
                    // Login action
                    ((Button)v).setText(TEXT_LOGOUT);
                    isLogin = false;
                } else {
                    // Logout action
                    ((Button)v).setText(TEXT_LOGIN);
                    isLogin = true;
                    // Redirect here or do an custom action
                }
                break;
        }
    }
}

Answer 3

在你的登录按钮onClick Listener上试试这种方式

login.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
    if(login.getText().toString().equals("Login")){
    doLogin(); //login functionality here
    }else{
    doLogout();//logout functionality here
    }
}});

Answer 4

一个简单的解决方案是

         logOutButton.setOnClickListener(new OnClickListener()){

               @Override
               public void onClick(View view){

                   String buttonText =  logOutButton.getText().toString();

                   if(buttonText.equalsIgnoreCase("Login")){

                       //let the user login, and change to logout after

                   }else if(buttonText.equalsIgnoreCase("Logout")){

                       //let the user logout and change to login after

                    }
             }

         });

Answer 5

@Override
public void onClick(View view){
     String buttonText =  logOutButton.getText().toString();
     if(buttonText.equalsIgnoreCase("Login")){   
          // logIn code here                    
          view.setText("Logout");
     }else{
          // logOut code here
          view.setText("Login");
        }
     }

如何在android中按钮文本更改后更改按钮操作

5 个答案: