Question

这是＆＃34;搜索框＆＃34;的PHP代码。我将在我的网站上加入。当我尝试通过输入关键字搜索我的数据库时出现以下错误。

注意：未定义的索引：第14行的C：\ xampp \ htdocs \ abell12 \ search.php中的searchterm

...这是完整的PHP代码

的index.php

    <!doctype html>
    <html>
    <head>
    <meta charset="utf-8">
    <title>Search (with keywords) Tutorial</title>
    </head>

    <body>
    <form action="search.php" method="POST">
        <input type="text" name="searchterm" placeholder="Search..."><br />
        <input type="submit" value="Search">
    </form>
    </body>
    </html>

的search.php

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Search (with keywords) Tutorial</title>
</head>

<body>
<?php

mysql_connect("127.0.0.1","root","root");
mysql_select_db("dummy_info");

$search = mysql_real_escape_string($_POST['searchterm']);

$find_books = mysql_query("SELECT * FROM `listings` WHERE `title` LIKE'%$search%'");
while($row = mysql_fetch_assoc($find_books))
{
    $title = $row['title'];


    echo "$title<br />";

}

?>
</body>
</html>

Answer 1

您应该先检查是否设置了$ _POST ['searchterm']。只有在提交表单时才会设置它。

也不要使用Mysql_函数。它们已被弃用。建议您使用MySQLI，因为它们可以防止SQL注入攻击等。

if(isset($_POST['searchterm']))
{
    $search = mysql_real_escape_string($_POST['searchterm']);

    $find_books = mysql_query("SELECT * FROM `listings` WHERE `title` LIKE '%$search%'");

    if(mysql_num_rows($find_books) > 0)
    {
        while($row = mysql_fetch_assoc($find_books))
        {
            $title = $row['title']; 
            echo "$title<br />";
        }
    }
    else
    {
        echo "No Record found";
    }
}

PHP搜索出错

1 个答案: