Question

我正在使用asp.net mvc 4进行服务。我需要能够从客户端应用程序接受POSTED图像/文件。我写了一个代码，它工作正常，但现在2到3周后，它不工作显示异常

CustomMultipartstreamprovider抛出异常

不知道有什么问题需要一些帮助。

我的代码是

public class UploadController : ApiController
    {
        private static IExceptionLogs _iException = new ExceptionLogsBLO();
        private readonly static string className = "Upload";
        private static string methodName = string.Empty;

        public async Task<HttpResponseMessage> PostFile() 
        {
            methodName = "PostFile";

            // Check if the request contains multipart/form-data.
            if (!Request.Content.IsMimeMultipartContent())
            {
                throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
            }

            //string root = HttpContext.Current.Server.MapPath("~/App_Data");
            string root = HttpContext.Current.Server.MapPath("~/Files");

            var provider = new CustomMultipartFormDataStreamProvider(root);
            //var task = Request.Content.ReadAsMultipartAsync(provider).ContinueWith();

            try
            {
                StringBuilder sb = new StringBuilder(); // Holds the response body
                string senderID = null;
                string receiverId = null;
                string Exten = null;
                Int64 Type = 0;
                Int64 IsGroup = 0;
                // Read the form data and return an async task.
                await Request.Content.ReadAsMultipartAsync(provider);

                // This illustrates how to get the form data.
                foreach (var key in provider.FormData.AllKeys)
                {
                   // Trace.WriteLine(key.Headers.ContentDisposition.FileName);


                    foreach (var val in provider.FormData.GetValues(key))
                    {
                        sb.Append(string.Format("{0}: {1}\n", key, val));
                        if (key == "senderId") 
                        {
                            senderID = val;
                        }
                        else if(key == "receiverId")
                        {
                             receiverId = val;
                        }
                        else if(key == "exten")
                        {
                            Exten = val;
                        }
                        else if (key == "fileType") 
                        {
                            if (val == "image")
                            {
                                Type = 1;
                            }
                            else if (val == "audio")
                            {
                                Type = 2;
                            }
                            else if (val == "video")
                            {
                                Type = 4;
                            }
                            else 
                            {
                                Type = 3;
                            }
                        }
                        else if (key == "IsGroup")
                        {

                            IsGroup = Convert.ToInt64(val);
                        }

                    }
                }

                // This illustrates how to get the file names for uploaded files.
                foreach (var file in provider.FileData)
                {
                    FileInfo fileInfo = new FileInfo(file.LocalFileName);
                    sb.Append(string.Format("Uploaded file: {0} ({1} bytes)\n", fileInfo.Name, fileInfo.Length));

                    // file save in database code 
                    FileUploadModel fileData = new FileUploadModel();

                    fileData.FileName = fileInfo.Name;
                    fileData.FileType = Type;
                    fileData.SenderId = Convert.ToInt64(senderID);
                   // fileData.ReceiverId = Convert.ToInt64(receiverId);
                    fileData.ReceiverId = receiverId;
                    fileData.FileExten = Exten;
                    fileData.IsRead = Convert.ToBoolean(0);
                    fileData.date = DateTime.Now.ToUniversalTime();
                    fileData.IsGroup = IsGroup;

                    FileUploadBLO fileBlo = new FileUploadBLO();

                    DbResult result = fileBlo.FileUploadData(fileData);

                }
                return new HttpResponseMessage()
                {
                    Content = new StringContent(sb.ToString())
                };
            }
            catch(Exception ex)
            {
                ExceptionLogsModel error = new ExceptionLogsModel(ex.Message, ex.StackTrace.ToString(), DateTime.Now, className, methodName);
                _iException.InsertException(error);

            }

            return null;

        }

    }



 class CustomMultipartFormDataStreamProvider : MultipartFormDataStreamProvider
    {
        public CustomMultipartFormDataStreamProvider(string path)
            : base(path)
        { }

        public override string GetLocalFileName(HttpContentHeaders headers)
        {
            return headers.ContentDisposition.FileName.Replace("\"", string.Empty);
           // var name = !string.IsNullOrWhiteSpace(headers.ContentDisposition.FileName) ? headers.ContentDisposition.FileName : "NoName";
           // return name.Replace("\"", string.Empty); //this is here because Chrome submits files in quotation marks which get treated as part of the filename and get escaped
        }
    }

Answer 1

在我的情况下，文件上载目标文件夹（保存文件）与Web应用程序目录链的虚拟目录不同，发生此异常。作为一个明显的解决方案，将文件目标文件夹保留为Web应用程序目录的一部分，工作进程将具有保存文件的适当访问权限。讨厌的部分是例外，不说它:(像'拒绝访问'......奇怪的例外。

希望它有所帮助，

CustomMultipartstreamprovider抛出和异常

1 个答案: