如何正确地从innerXMl获取值

时间:2014-05-27 00:38:24

标签: c# arrays xml unity3d nested

我打算在数组中检索每个建议,然后将其输入列表。我无法检索选项节点数据,在这种模式中{飞机,飞机,空中飞行} {i},任何善良的灵魂都可以帮助我解决它。

XmlDocument findStringDoc = new XmlDocument();
    findStringDoc.Load (Application.dataPath+ "/" + filename);
    XmlNodeList nodeList = findStringDoc.SelectNodes("/results/error");
    //XmlNodeList suggestionNodeList = findStringDoc.SelectNodes("/results/error/suggestions/option");
    foreach(XmlNode xn in nodeList){
        errorString.Add(xn["string"].InnerText);
        errorType.Add(xn["type"].InnerText);
        //string temp = xn["suggestion"].InnerXml;

        ////TODO: Retrieve suggestions here!
        XmlNodeList suggestionNodeList = findStringDoc.SelectNodes("/suggestions");
        foreach(XmlNode yn in suggestionNodeList){
            option[suggestionNodeList.Count] = yn["option"].InnerText;
            Debug.Log(yn["option"].InnerText);
        }
        suggestionResult.Add (option);
        //Debug.Log(suggestionResult);

        //XmlNodeList suggestionNodeList = findStringDoc.SelectNodes("/results/error[string='{0}']/suggestions/option",errorString[i]);
    }


<results>
  <error>
    <string>aeroplan</string>
    <description>Spelling</description>
    <precontext>a</precontext>
    <suggestions>
        <option>aeroplane</option>
        <option>aeroplanes</option>
        <option>aerobian</option>
    </suggestions>
    <type>spelling</type>
  </error>
  <error>
    <string>i</string>
    <description>Make I uppercase</description>
    <precontext></precontext>
    <suggestions>
        <option>I</option>
    </suggestions>
    <type>grammar</type>
    <url>http://service.afterthedeadline.com/info.slp?text=i&amp;tags=PRP&amp;engine=1</url>
  </error>
</results>

2 个答案:

答案 0 :(得分:1)

您可以使用我的代码:

private static void GetSuggestionOption(string filename, string value, string optionSuggest)
        {
            XDocument xDoc = XDocument.Parse(filename);
            var parentNode = xDoc.Descendants().Where(x => x.Value == value).Ancestors().FirstOrDefault();
            var childNode = parentNode.Descendants().Where(x => x.Name == optionSuggest);
            childNode.ToList().ForEach(x => Console.WriteLine(x.Value));
        }

调用:GetSuggestionOption(fileName,&#34; aeroplan&#34;,&#34;选项&#34;);

快乐的编码!

答案 1 :(得分:1)

您可以使用XmlDocument.SelectNodes()方法传递合适的XPath字符串参数来从XmlDocument中选择特定元素,例如:

public void GetSuggestionOption(string keyword)
{
    XmlDocument doc = new XmlDocument();
    doc.Load (Application.dataPath+ "/" + filename);
    string xpath = string.Format("//error[string='{0}']/suggestions/option", keyword);
    XmlNodeList optionSuggestionList = doc.SelectNodes(xpath);
    foreach (XmlNode option in optionSuggestionList)
    {
        Debug.Log(option.InnerXml);
    }
}

您可以通过这种方式调用方法,例如:GetSuggestionOption("aeroplan")