Question

在设置构造函数时，是否有可能将其参数传递给其中一个方法？这就是我的意思：

function jedi(name,text){
    this.name = name;
    this.quote = function quote(name,text){
         return name + " said " + text;
    };
}

 var obiwan = new jedi('Obi-Wan','Fear leads to the darkside');
 console.log(obiwan.quote());  //renders as undefined said undefined

 //this works fine though
 console.log(obiwan.quote('Obi-Wan','Fear leads to the darkside'));

是否可以将'name'和'text'参数直接从'var obiwan = new jedi（）'传递给'obiwan.quote（）'？我希望我的问题有道理。在此先感谢任何可以帮助我的人！

Answer 1

只需使用实例变量吗？

function jedi(name,text){
    this.name = name;
    this.text = text;

    this.quote = function quote(){
         return this.name + " said " + this.text;
    };
}

 var obiwan = new jedi('Obi-Wan','Fear leads to the darkside');
 console.log(obiwan.quote());  //works like a charm

Answer 2

为quote函数的参数赋予不同的名称，而不是给予构造函数参数的名称。

function jedi(name,text){
    this.name = name;
    this.quote = function quote(_name,_text){
         return (_name || name)  + " said " + (_text || text);
    };
}

var obiwan = new jedi('Obi-Wan','Fear leads to the darkside');

console.log(obiwan.quote());  
// would rendera as Obi-Wan said Fear leads to the darkside

console.log(obiwan.quote('I', "is the new X-men inspired from Assassin's Creed?"));
// would rendera as I said is the new X-men inspired from Assassin's Creed?

将javascript参数从对象构造函数传递给对象的方法？

2 个答案: