Question

我的数据类似于：

Date        UserID    Visits
2012-01-01  2         5
...

我想输出一个拥有＆gt;的用户列表x访问至少y个日期（例如，从1月3日到1月10日至少3个日期有> 5次访问的用户）。

Answer 1

试试这个：

SELECT SUB.UserId, COUNT(*) FROM (
     SELECT VL.UserId FROM VisitLog VL
        WHERE VL.Visits > 5
              AND VL.Date BETWEEN '2014-01-03' AND '2014-01-10') SUB
   GROUP BY SUB.UserId
   HAVING COUNT(*) >= 3

子查询返回样本日期范围之间Visits > 5个数的所有行。然后计算结果，仅返回此条件至少匹配3次的用户。

您没有提供太多信息，但如果每个用户每个日期有多个记录，则使用此查询（完全相同的主体，只是按用户和日期求和的内部分组）：

SELECT SUB.UserId, COUNT(*) FROM (
     SELECT VL.UserId, VL.Date FROM VisitLog VL
            WHERE VL.Date BETWEEN '2014-01-03' AND '2014-01-10'
            GROUP BY VL.UserId, VL.Date 
            HAVING SUM(VL.Visits) > 5) SUB
   GROUP BY SUB.UserId
   HAVING COUNT(*) >= 3

Answer 2

Select UserID,SUM(Visits) from TableOfData
where Date>@HereTheDate
group by UserID
having SUM(Visits)>5

Answer 3

试试这个：

select * from users
where id in (
    select UserID
    from userVisits
    where date between '2014-01-03' and '2014-01-10'
    and visits >= 5
    group by userid
    having count(*) >= 3)

SQL：满足条件N次的用户列表

3 个答案: